Answer:
1.53 L
Explanation:
Step 1: Given data
- Mass of oxygen (m): 11.2 g
- Ideal gas constant (R): 0.0821 atm.L/mol.K
Step 2: Calculate the moles (n) corresponding to 11.2 g of oxygen
The molar mass of oxygen is 32.00 g/mol.
11.2 g × (1 mol/32.00 g) = 0.350 mol
Step 3: Calculate the volume of oxygen
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 0.350 mol × (0.0821 atm.L/mol.K) × 415 K / 7.78 atm
V = 1.53 L
25% of 20
%=100
25/100 x 20
1/4 x 20
The answer is equal to 5
Answer:
The correct answer is (D) All of the above.
Explanation:
A chemical bond is the attraction force between atoms (covalent bond) or between oppositely charged ions (ionic bond) to form a stable arrangement. In order to get a stable arrangement must be fulfilled the octet rule. This establishes that an atom could share (covalent bond) win or lose (ionic bond) electrons with other atoms till every atom has eight valence electrons. The complete outer shell of valence electrons make elements stable to get a stable noble gas configuration.
Concentration is the number of moles of solute in a fixed volume of solution
Concentration(c) = number of moles of solute(n) / volume of solution (v)
25.0 mL of water is added to 125 mL of a 0.150 M LiOH solution and solution becomes more diluted.
original solution molarity - 0.150 M
number of moles of LiOH in 1 L - 0.150 mol
number of LiOH moles in 0.125 L - 0.150 mol/ L x 0.125 L = 0.01875 mol
when 25.0 mL is added the number of moles of LiOH will remain constant but volume of the solution increases
new volume - 125 mL + 25 mL = 150 mL
therefore new molarity is
c = 0.01875 mol / 0.150 L = 0.125 M
answer is 0.125 M
