Answer:
V1 = 2221.33 L
Explanation:
The system is about a ideal gas. Then you can use the equation for ideal gases for a volume V1, temperature T1 and pressure P1:
(1)
And also for the situation in which the variables T, V and P has changed:
(1)
R: constant of ideal gases = 0.082 L.atm/mol.K
For both cases (1) and (2) the number of moles are the same. Next, you solve for n in (1) and (2):

Next, you equal these equations an solve for T2:

Finally you replace the values of P2, V2, T1 and T2:

Hence, the initial volume of the gas is 2221.33 L
Answer:
48.4293354946 N
Yes
Explanation:
d = Diameter of rod = 2.95 cm
h = Length of rod = 92.6 cm
= Density of rod = 7800 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
Volume of rod

Mass is given by

Weight is given by

The weight of the rod is 48.4293354946 N
The mass of the rod is 4.93673144695 kg which is light. So, I will be able to carry the rod without a cart.
Answer:https://www.khanacademy.org/science/high-school-physics/electric-charge-and-electric-force/coulombs-law-and-electric-force/v/coulombs-law
Explanation: Here is a link to a video that might help you
I assume here that the engine operates following a Carnot cycle, which achieves the maximum possible efficiency.
Under this assumption, the efficiency of the engine (so, the efficiency of the Carnot cycle) is given by

where

is the cold temperature

is the hot temperature
For the engine in our problem, the cold temperature is 313 K while the hot temperature is 425 K, so the effiency of the engine is
Answer:
Explanation:
ΔE = Δm × c^2
where,
ΔE = change in energy released with respect to change in mass
= 1.554 × 10^3 kJ
= 1.554 × 10^6 J
Δm = change in mass
c = the speed of light.
= 3 × 10^8 m/s
Equation of the reaction:
2H2 + O2 --> 2H2O
Mass change in this process, Δm = 1.554 × 10^6/(3 × 10^8)^2
= 1.727 × 10^-11 kg
The change in mass calculated from Einstein equation is small that its effect on formation of product will be negligible. Hence, law of conservation of mass holds correct for chemical reactions.