particle moves over three quarters of a circle of radius R what is the magnitude of its displacement
1 answer:
You might be interested in
So, the speed of the ball after 2 seconds after free fall is <u>20 m/s</u>.
<h3>Introduction</h3>Hi ! I'm Deva from Brainly Indonesia. In this material, we can call this event "Free Fall Motion". There are two conditions for free fall motion, namely falling (from top to bottom) and free (without initial velocity). Because the question only asks for the final velocity of the ball, in fact, we may use the formula for the relationship between acceleration and change in velocity and time. In general, this relationship can be expressed in the following equation :
With the following conditions :
- a = acceleration (m/s²)
= speed after some time (m/s)
= initial speed (m/s)
- t = interval of time (s)
We know that :
- a = acceleration = 9,8 m/s² >> because the acceleration of a falling object is following the acceleration of gravity (g).
- t = interval of time = 2 s
What was asked :
Step by step :
So, the speed of the ball after 2 seconds after free fall is 20 m/s.