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Murljashka [212]
3 years ago
10

Which statements about velocity are true?

Physics
2 answers:
OleMash [197]3 years ago
5 0
<span>the speed of a direction</span>
iVinArrow [24]3 years ago
3 0

The answer is "It has magnitude and direction."

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The 'little brain' attached to the rear of the brainstem is called the: (2 points)
11111nata11111 [884]

Answer:

The 'little brain' attached to the rear of the brainstem is called the cerebellum. See the explanation below, please.

Explanation:

The cerebellum is in the back of the brain, it is small in size. It is responsible for functions such as integrations of sensory and motor pathways, balance, coordination of movements, posture.

6 0
3 years ago
Read 2 more answers
A 40 Watt lightbulb is on for 3 minutes. How many joules of work does it do?
ella [17]

Answer:

Explanation:

Power (p)= 40 watt

time (t)= 3 minutes = 180 seconds

Energy (E)= ?

we know

P = E/t

40 = E / 180

E = 7200 Joules

Therefore it does 7200 joules of work.

hope it helps :)

6 0
2 years ago
This is science :)
iris [78.8K]
1 to 5 would be your answer
8 0
2 years ago
You want to manufacture a guitar such that the instrument will be in tune when each of the strings are tightened to the same ten
charle [14.2K]

Answer:

0.000507 kg/m

Explanation:

L = Length of string

T = Tension

\mu = Mass density of string

E denotes the E string

D denotes the D String

Frequency is given by

f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}

So

f\propto \sqrt{\dfrac{1}{\mu}}

\dfrac{f_D}{f_E}=\sqrt{\dfrac{\mu_E}{\mu_D}}\\\Rightarrow \mu_E=\dfrac{f_D^2}{f_E^2}\mu_D\\\Rightarrow \mu_E=\dfrac{146.83^2}{329.63^2}\times 0.00256\\\Rightarrow \mu_E=0.000507\ kg/m

The mass density of the E string is 0.000507 kg/m

8 0
3 years ago
A thin film of soap with n = 1.34 hanging in the air reflects dominantly red light with λ = 642 nm. What is the minimum thicknes
wariber [46]

Answer:

The minimum thickness of the film and the wavelength of the light in air are 1.197\times10^{-7}\ m and 371 nm.

Explanation:

Given that,

Refractive index of soap= 1.34

Refractive index  of glass= 1.55

Wavelength = 642 nm

(I). We need to calculate the minimum thickness

Using formula of thickness

t=\dfrac{(2m+1)\lambda}{4n}

Where, m = 0 for constrictive

Put the value into the formula

t=\dfrac{(642\times10^{-9})}{4\times1.34}

t=1.197\times10^{-7}\ m

(II). We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{2nt}{m}

Where, m = 1

Put the value into the formula

\lambda=\dfrac{2\times1.55\times1.197\times10^{-7}}{1}

\lambda=371\ nm

Hence, The minimum thickness of the film and the wavelength of the light in air are 1.197\times10^{-7}\ m and 371 nm.

6 0
3 years ago
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