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Jlenok [28]
2 years ago
6

Sam was investigating a container of water. Water can be a solid, liquid, or gas. At first, Sam said the water molecules were mo

ving around each other. Later, the water molecules were moving in place. What change did they observe to the water?
At first, the water was a gas. Later, it was a liquid.
At first, the water was a liquid. Later, it was a solid.
At first, the water was a solid. Later, it was a liquid.
At first, the water was a liquid. Later, it was a gas.
Physics
2 answers:
Andreyy892 years ago
8 0

Answer:

At first, the water was a gas. Later, it was a liquid.

Explanation:

aleksandr82 [10.1K]2 years ago
4 0

Answer:

A) At first, the water was a gas. Later, it was a liquid.

Explanation:

The molecules of a solid cant move at all, so therefore we can knock out B and C. Moleculaes move more freely in a gas form than in a water form, so therefore the firt form has to be a gas, so knock out the answer choice D, which keaves you with A. I hope this helps :)

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How much energy in calories does it take to melt 10 grams of ice?
Nikitich [7]

Answer:

800 calories

Explanation:

3 0
2 years ago
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Your friend wants to join the school track team, and has asked for your help to determine how fast she can run. 4. What kind of
DENIUS [597]

Answer:

I think you would need too time your friend and know how too divide that time by other racers to see how much faster she needs to get. I THINK.

7 0
2 years ago
A flask contains equal masses of f2 and cl2 with a total pressure of 2.00 atm at 298k. What is the partial pressure of cl2 in th
Sindrei [870]

Answer:

Partial Pressure of F₂ = 1.30 atm

Partial pressure of Cl₂ = 0.70 atm

Explanation:

Partial pressure for gases are given by Daltons law.

Total pressure of a gas mixture = sum of the partial pressures of individual gases

Pt = P(f₂) + P(cl₂)

Partial pressure = mole fraction × total pressure

Let the mass of each gas present be m

Number of moles of F₂ = m/38 (molar mass of fluorine = 38 g/Lol

Number of moles of Cl₂ = m/71 (molar mass of Cl₂)

Mole fraction of F₂ = (m/38)/((m/38) + (m/71)) = 0.65

Mole fraction of Cl₂ = (m/71)/((m/38) + (m/71)) = 0.35 or just 1 - 0.65 = 0.35

Partial Pressure of F₂ = 0.65 × 2 = 1.30 atm

Partial pressure of Cl₂ = 0.35 × 2 = 0.70 atm

7 0
2 years ago
Suppose that the electric field in the Earth's atmosphere is E = 8.60 101 N/C, pointing downward. Determine the electric charge
asambeis [7]

Answer:

q = 3.87 x 10⁵ C

Explanation:

given,

Electric field, E = 8.60 x 10¹ = 86 N/C

radius of earth, R = 6371 Km = 6.371 x 10⁶ m

Coulomb constant, K = 9 x 10⁹ N · m²/C²

Charge on the earth = ?

the electric field at the point

E =\dfrac{kq}{r^2}

q =\dfrac{Er^2}{k}

inserting all the values

q =\dfrac{86\times (6.371\times 10^6)^2}{9\times 10^{9}}

      q = 3.87 x 10⁵ C

The electric charge on the earth is equal to 3.87 x 10⁵ C

4 0
3 years ago
Two forces and are applied to an object whose mass is 13.3 kg. The larger force is . When both forces point due east, the object
ANEK [815]

Answer:

Explanation:

First, It's important to remember F = ma, and in this problem m = 13.3 kg

This can be reduced to a simple system of equations problem.  Now if they are both going the same way then we add them, while if they are going the opposite way we subtract them.  So let's call them F1 and F2, with F1 arger than F2.  Now, When we add them together F1+F2 = (.723 m/s^2)*13.3kg and then when we subtract them, and have the larger one pushing toward the east, let's call F1 the larger one, F1-F2 = (.493 m/s^2)*13.3kg.  

Can you solve this system of equations seeing them like this, or do you need more help?

6 0
2 years ago
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