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Jlenok [28]
2 years ago
6

Sam was investigating a container of water. Water can be a solid, liquid, or gas. At first, Sam said the water molecules were mo

ving around each other. Later, the water molecules were moving in place. What change did they observe to the water?
At first, the water was a gas. Later, it was a liquid.
At first, the water was a liquid. Later, it was a solid.
At first, the water was a solid. Later, it was a liquid.
At first, the water was a liquid. Later, it was a gas.
Physics
2 answers:
Andreyy892 years ago
8 0

Answer:

At first, the water was a gas. Later, it was a liquid.

Explanation:

aleksandr82 [10.1K]2 years ago
4 0

Answer:

A) At first, the water was a gas. Later, it was a liquid.

Explanation:

The molecules of a solid cant move at all, so therefore we can knock out B and C. Moleculaes move more freely in a gas form than in a water form, so therefore the firt form has to be a gas, so knock out the answer choice D, which keaves you with A. I hope this helps :)

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As a 5.0 × 10^2-newton basketball player jumps
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     This player is initially at rest, then the Force Weight (W) and the Normal Force (N) have a same module. When applies a Extra Force (E) on the floor, this reacts with this increase, causing the player to be released upwards.
     Using the Newton's Secound Law, we have:

F_{R}=ma \\ W+E-N=ma \\ N =W+E \\ N=5*10^2+10*10^2 \\ \boxed {N=1.5*10^3N}

Number 3

If you notice any mistake in my english, please let me know, because i am not native.
4 0
3 years ago
If Angle "a" is 25°, Angle "b" is:
Leokris [45]
I would say B but I have no clue
6 0
3 years ago
If an object is not moving, what do we know about the forces acting on it?
Nat2105 [25]
I think it should be 'They are balanced' if I'm not wrong
7 0
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Read 2 more answers
In Example 2.7, we investigated a jet landing on an aircraft carrier. In a later maneuver, the jet comes in for a landing on sol
igor_vitrenko [27]

Answer:

a) 20 seconds

b) No.

Explanation:

t = Time taken for jet to stop

u = Initial velocity = 100 m/s (given in the question)

v = Final velocity = 0 (because the jet will stop at the end)

s = Displacement of the jet (Distance between the moment the jet touches the ground to the point the point it stops)

a = Acceleration = -5.00 m/s² (slowing down, so it is negative)

a) Equation of motion

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-100}{-5}\\\Rightarrow t=20\ s

The time required for the plane to slow down from the moment it touches the ground is 20 seconds.

s=ut+\frac{1}{2}at^2\\\Rightarrow s=100\times 20+\frac{1}{2}\times -5\times 20^2\\\Rightarrow s=1000\ m

The distance it requires for the jet to stop is 1000 m so in a small tropical island airport where the runway is 0.800 km long the plane would not be able to land. The runway needs to be atleast 1000 m long here the runway on the island is 1000-800 = 200 m short.

5 0
3 years ago
How much mass should be attached to a vertical ideal spring having a spring constant (force constant) of 39.5 n/m so that it wil
mrs_skeptik [129]
The frequency of a simple harmonic oscillator such as a spring-mass system is given by
f= \frac{1}{2 \pi}   \sqrt{ \frac{k}{m} }
where 
k is the spring constant
m is the mass attached to the spring.

Re-arranging the formula, we get:
m= \frac{k}{4 \pi^2 f^2}
and since we know the constant of the spring:
k=39.5 N/m
and the frequency of oscillation:
f=1.00 Hz
we can find the value of the mass attached to it:
m= \frac{39.5 Hz}{4 \pi^2 (1.00 Hz)^2} = 1.00 kg
7 0
3 years ago
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