1) Forces acting on your body: force of gravity and normal reaction
2) Due to Newton's second law, N = mg
Explanation:
1)
When you sit on the computer, there are only two forces acting on you:
- The force of gravity, acting downward, of magnitude , where m is your mass and is the acceleration due to gravity, downward
- The normal reaction exerted by the chair on you, , acting upward
Your body is in equilibrium (it doesn't move), this means that the two forces balance each other, therefore:
2)
We can now apply Newton's second law of motion to this situation; this law states that the net force acting on a body is equal to the product between its mass and its acceleration. Mathematically,
where
is the net force
m is the mass
a is the acceleration
In this situation, the net force is
So the equation becomes
However, we observe that your body is at rest; therefore, the acceleration is zero:
a = 0
And therefore,
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By Newton's second law, the net force on the object is
∑ <em>F</em> = <em>m</em> <em>a</em>
∑ <em>F</em> = (2.00 kg) (8 <em>i</em> + 6 <em>j</em> ) m/s^2 = (16.0 <em>i</em> + 12.0 <em>j</em> ) N
Let <em>f</em> be the unknown force. Then
∑ <em>F</em> = (30.0 <em>i</em> + 16 <em>j</em> ) N + (-12.0 <em>i</em> + 8.0 <em>j</em> ) N + <em>f</em>
=> <em>f</em> = (-2.0 <em>i</em> - 12.0 <em>j</em> ) N
When balanced forces follow up on an object, the object won't move. If you push against a wall, the wall pushes back with an equal but opposite force. Neither you nor the wall will move. Forces that cause a change in the motion of an object are unbalanced forces.
85.689 kg is the astronaut's mass.
<u>Explanation:</u>
Given data: m = 22.5 kg and T = 1.3 sec
So, using the below formula,
Now, after putting the values of m and T in the above equation, we will find out the value of k which is as,
To remove the square root, take square on both sides, we get,
Now, we have the same string but this time we have different mass and different time. So, let the mass of the astronaut is and = 2.54 sec, k= 525.7 kg. Apply these values in the equation, we get,
Taking squares on both sides, we get,
the water specific heat will remain at 4.184.