The rocket would have gone 125 m away in deep space.The speed when it has gone 300 m is 76.7 m/s.
Answer:
The distance the rocket traveled is 125 m. The speed when it has gone 300 m is 76.7 m/s.
Explanation:
According to the equations of motion, if an object is moving with constant acceleration, then the distance travelled by the object with that acceleration and within a specific time can be obtained as
Since the initial velocity is given as u = 0 at t = 0. Then at t = 10 s, the acceleration is given by 2.5 m/.
Thus,
s= 0 + (×2.5×)=125 m.
Thus, the rocket would have gone 125 m away in deep space.
Similarly, if it had gone 300 m then its speed can be determined using the third equation of motion.
Since, here v is unknown and u is known as 0 with a = 2.5 m/.
2× 9.8×300=v²
5880=v²
Thus, the speed v =
So, the speed when it has gone 300 m is 76.7 m/s.
∆y is change in y (velocity) and ∆x is change in x (time)
So from the graph we see that ∆y is zero and ∆x is also zero (value is changing with same ratio)
∆y/∆x= slope = 0
Answer:
Because the Sun shines by nuclear fusion, which converts mass into energy as hydrogen turns into helium. ... A typical star that is the source of light and heat for the planets in the solar system.
Explanation:
Answer:
It is possible for neutral objects to become charged by rubbing them together due to friction. Electrons of one object transfer to the other resulting to more electrons in the object than its protons therefore leaving it as charged
Explanation:
I all ready said it 0>0