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KonstantinChe [14]
3 years ago
15

When balancing redox reactions under basic conditions in aqueous solution, the first step is to:________.

Chemistry
1 answer:
natta225 [31]3 years ago
3 0

Answer:

When balancing redox reactions under basic conditions in aqueous solution, the first step is to balance oxygen.

Explanation:

Oxidation-reduction reactions or redox reactions are those in which an electron transfer occurs between the reagents. An electron transfer implies that there is a change in the number of oxidation between the reagents and the products.

The gain of electrons is called reduction and the loss of electrons oxidation. That is to say, there is oxidation whenever an atom or group of atoms loses electrons (or increases its positive charges) and in the reduction an atom or group of atoms gains electrons, increasing its negative charges or decreasing the positive ones.

The oxidation and reduction half-reactions, in a basic medium, adjust the oxygens and hydrogens as follows:

In the member of the half-reaction that presents excess oxygen, you add as many water molecules as there are too many oxygen. Then, in the opposite member, the necessary hydroxyl ions are added to fully adjust the half-reaction. Normally, twice as many hydroxyl ions, OH-, are required as water molecules have previously been added.

In short, you first adjust the oxygens with OH-, then you adjust the H with H₂O, and finally you adjust the charge with e-

So, <u><em>when balancing redox reactions under basic conditions in aqueous solution, the first step is to balance oxygen.</em></u>

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One of the emission spectral lines for Be3+ has a wavelength of 253.4 nm for an electronic transition that begins in the state w
4vir4ik [10]

Answer:

4

Explanation:

Relationship between wavenumber and Rydberg constant (R) is as follows:

wave\ number=R\times Z^2\frac{1}{n_1^2} -\frac{1}{n_1^2}

Here, Z is atomic number.

R=109677 cm^-1

Wavenumber is related with wavelength as follows:

wavenumber = 1/wavelength

wavelength = 253.4 nm

wavenumber=\frac{1}{253.4\times 10^{-9}} \\=39463.3\ cm^{-1}

Z fro Be = 4

39463.3=109677\times 4^2(\frac{1}{n_1^2} -\frac{1}{5^2})\\39463.3=109677\times 16(\frac{1}{n_1^2} -\frac{1}{5^2})\\n_1=4

Therefore, the principal quantum number corresponding to the given emission is 4.

6 0
3 years ago
Express the following number in scientific notation: 0.000000675.
tekilochka [14]
There are 7 digits from decimal to 1st digit, and it's coming from right, so exponent will be in negative 7

In short, Your Answer would be: Option C) <span>6.75 × 10-7
</span>
Hope this helps!
6 0
3 years ago
Find the pH of a solution whose H concentration is 0.7 x 10-3.
dexar [7]

Answer: pH = 3.15

Explanation: Solved in the attached picture.

6 0
2 years ago
What does evaporation produce?
baherus [9]

Answer:

C. Water Vapor

Explanation:

Hope this helps! Have an Amazing day!!

7 0
2 years ago
Read 2 more answers
A 20 kg curling stone is sliding in a positive direction at 4 m/s. A second curling stone is sliding at the same speed but in th
solniwko [45]

Answer:

The kinetic energy of the two stones is 320 J

Explanation:

Kinetic energy is the energy that a body possesses due to its movement. So it is the capacity or work that allows an object to go from being at rest, or still, to moving at a certain speed.

In other words, the kinetic energy of an object is that which is produced due to its motion and depends on its mass and velocity as follows:

Ec=\frac{1}{2} *m*v^{2}

where the kinetic energy Ec is measured in joules (J), the mass m is measured in kilograms (kg) and the velocity v in meters/second (m/s).

In this case you know that a 20 kg curling stone is sliding in a positive direction at 4 m/s. So:

  • m= 20 kg
  • v= 4 m/s

Replacing you have:

Ec_{1} =\frac{1}{2} *20 kg*(4\frac{m}{s}) ^{2}

Ec₁= 160 J

A second curling stone slides at the same speed but in the opposite direction. So:

  • m= 20 kg
  • v= - 4 m/s

Replacing you have:

Ec_{2} =\frac{1}{2} *20 kg*(-4\frac{m}{s}) ^{2}

Ec₂= 160 J

The kinetic energy of the two stones is calculated as:

Ec= Ec₁ + Ec₂

Ec= 160 J + 160 J

Ec= 320 J

<u><em>The kinetic energy of the two stones is 320 J</em></u>

7 0
3 years ago
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