Answer:
3.57 g.
Explanation:
- The ratio of cream of tartar (KHC₄H₄O₆) to baking soda (NaHCO₃) in the baking powder is 1:1.
- We need to calculate the number of moles of (8.0 g) of cream of tartar (KHC₄H₄O₆) using the relation:<em> n = mass / molar mass,</em>
mass of cream of tartar (KHC₄H₄O₆) = 8.0 g.
molar mass of cream of tartar (KHC₄H₄O₆) = 188.1772 g/mol.
∴ n of cream of tartar (KHC₄H₄O₆) = mass /molar mass = (8.0 g) / (188.1772 g/mol) = 0.0425 mol.
- Since the mole ratio of the two components is 1:1, the no. of moles of baking soda (NaHCO₃) should be added is 0.0425 mol.
- The quantity of baking soda (NaHCO₃) can be calculated using the relation:
mass = n x molar mass = (0.0425 mol)(84.007 g/mol) = 3.57 g.
Answer:
107.8
Explanation:
64 gram of N2H4 produce 72 gram of H20
then by crossmultiplication
64*121.3/72=107.82
Answer:
The answer to your question is 3 moles of AlCl₃
Explanation:
Process
1.- Write and balance the equation
Al(NO₃)₃ + 3NaCl ⇒ 3NaNO₃ + AlCl₃
2.- Determine the limiting reactant
Theoretical proportion 1 mol Al(NO₃)₃ : 3 moles of NaCl
Experimental proportion 4 moles Al(NO₃)₃ : 9 moles NaCl
From these values, we determine that the limiting reactant is NaCl because the number of moles increases three times and the number of moles of Al(NO₃)₃ increases four times.
3.- Determine the amount of AlCl₃ using proportions
3 moles of NaCl --------------- 1 mol of AlCl₃
9 moles of NaCl ---------------- x
x = (9 x 1) / 3
x = 9 /3
x = 3 moles
