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victus00 [196]
3 years ago
8

Is it possible to have a single force?

Physics
1 answer:
katen-ka-za [31]3 years ago
8 0
Yes it is possible to have a single force, this is possible, check the example below :

Example 1. I'am pushing pushing the table closer to the wall.

If you have just finished reading the example above , you should now know that there is only one force that is active at the moment. The table doesn't have an active force because it cannot fight against mine. The only type of "defense" the table has is friction because of the rubbing against the floor.

I hope this helped you a lot,
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Answer: abdominal muscles.

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A heavy copper ball of mass 2 kg is dropped from a fiftieth-floor apartment window. Another one with mass 1 kg is dropped immedi
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Which of the following can be done to demagnetize a permanent magnet?
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4 years ago
A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23 m/s. If the ball was caught 42 m from the
ExtremeBDS [4]

Answer:

a) v_{0y} = 9.72 m/s

b) v_{0x} = 20.85 m/s

c) t = 2.01 s

d) h_{max} = 4.82 m

Explanation:

a) The initial vertical velocity is given by:

v_{0y} = v*sin(\theta)

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

v_{0y} = 23 m/s*sin(25) = 9.72 m/s

b) The initial horizontal velocity can be calculated as follows:

v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s

c) The flight time can be calculated using the following equation:

v_{0x} = \frac{x}{t}

Where:

x: is the total distance = 42 m

t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s

d) The maximum height is given by:

v_{fy}^{2} = v_{0y}^{2} - 2gh_{max}

Where:

v_{fy}: is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m

I hope it helps you!                                  

7 0
3 years ago
Help me guys pleasssseeee
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B. Kinetic energy increases, potential energy decreases.
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