Answer:
a push
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Explanation:
net ionic equation
B) SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)
Explanation:
We have the following chemical equation:
2 Na⁺ (aq) + SO₄²⁻ (aq) + Ba²⁺ (aq) + 2 Cl⁻ (aq) → 2 Na⁺ (aq) + 2 Cl⁻ (aq) + BaSO₄ (s)
To get the net ionic equation we remove the spectator ions and we get:
SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)
were:
(aq) - aqueous
(s) - solid
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net ionic equation
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Answer:
6.475 M
Explanation:
Number of moles = 25.9 moles
Volume = 4.00 L
Molarity = ?
The relationship between the quantities is given as;
Molarity = Number of moles / Volume
Molarity = 25.9 / 4
Molarity = 6.475 M
CaCl2 and KCl are both salts which dissociate in water
when dissolved. Assuming that the dissolution of the two salts are 100 percent,
the half reactions are:
<span>CaCl2 ---> Ca2+ + 2 Cl-</span>
KCl ---> K+ + Cl-
Therefore the total Cl- ion concentration would be coming
from both salts. First, we calculate the Cl- from each salt by using stoichiometric
ratio:
Cl- from CaCl2 = (0.2 moles CaCl2/ L) (0.25 L) (2 moles
Cl / 1 mole CaCl2)
Cl- from CaCl2 = 0.1 moles
Cl- from KCl = (0.4 moles KCl/ L) (0.25 L) (1 mole Cl / 1
mole KCl)
Cl- from KCl = 0.1 moles
Therefore the final concentration of Cl- in the solution
mixture is:
Cl- = (0.1 moles + 0.1 moles) / (0.25 L + 0.25 L)
Cl- = 0.2 moles / 0.5 moles
<span>Cl- = 0.4 moles (ANSWER)</span>
