Answer: There are
atoms of hydrogen are present in 40g of urea,
.
Explanation:
Given: Mass of urea = 40 g
Number of moles is the mass of substance divided by its molar mass.
First, moles of urea (molar mass = 60 g/mol) are calculated as follows.

According to the mole concept, 1 mole of every substance contains
atoms.
So, the number of atoms present in 0.67 moles are as follows.

In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.

Thus, we can conclude that there are
atoms of hydrogen are present in 40g of urea,
.
<em>the</em><em> </em><em>number</em><em> of</em><em> </em><em>nitrogen</em><em> </em><em>atoms</em><em> </em><em>in</em><em> </em><em>the </em><em>compound</em><em> </em><em>is</em><em> </em><em>two</em>
The term mole refers to 6.02x10²³ atoms or molecules of any substance. so regardless of the substance one mole will always be equivalent to 6.02x10²³
Hope that helps
Answer:
2N₂ + O₂ → 2N₂O
Explanation:
Given equation:
N₂ + O₂ → N₂O
In balancing a chemical equation, the number of atoms on both sides of the expression must be the same.
To solve this problem, we use a simple mathematical approach;
put coefficients a,b and c
aN₂ + bO₂ → cN₂O
Conserving N;
2a = 2c
Conserving O:
2b = c
Let a = 1, c = 1 , b = 
multiply through by 4
a = 2, b = 1 and c = 2
Balanced equation is;
2N₂ + O₂ → 2N₂O
<span>a. What is the empirical formula of the gas? In this case, the empirical formula is the same as the molecular formula
</span>
An empirical formula is a formula that gives the proportions of the elements present in a certain compound however it does not give the actual numbers or the arrangement of the atoms. To determine this, we do as follows:
H = (1.69)(.05) = 0.08 g ( 1 mol / 1.01 g ) = 0.0792 / 0.0792 = 1
F = (1.69)(.95) = 1.61 g ( 1 mol / 19 g ) = 0.0847 / 0.0792 = 1
The empirical formula would be HF.
<span>b. What is the molecular formula of the solid?
I bet there is a lacking information for the solid. We cannot determine the molecular formula with only the values given above. The closest would be the compound UF2O2.
</span><span>c. Write a balanced equation for the reaction between UF6 and H2O.
</span>2H2O + UF6 -> UF2O2 +4HF