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masya89 [10]
3 years ago
14

Choose the aqueous solution below with the highest freezing point. These are all solutions of nonvolatile solutes and you should

assume ideal van't Hoff factors where applicable.
(i) 0.200 m HOCH2CH2OH
(ii) 0.200 m Ba(NO3)2
(iii) 0.200 m K3PO3
(iv) 0.200 m Ca(CIO4)2
(v) These all have the same freezing point.
Chemistry
1 answer:
GrogVix [38]3 years ago
8 0

Answer:

0.200 m K3PO3

Explanation:

Let us remember that the freezing point depression is obtained from the formula;

ΔTf = Kf m i

Where;

Kf = freezing point constant

m = molality

i = Van't Hoff factor

The  Van't Hoff factor has to do with the number of particles in solution. Let us consider the  Van't Hoff factor for each specie.

0.200 m HOCH2CH2OH - 1

0.200 m Ba(NO3)2 - 3

0.200 m K3PO3 - 4

0.200 m Ca(CIO4)2 - 3

Hence, 0.200 m K3PO3 has the greatest van't Hoff factor and consequently the greatest freezing point depression.

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Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
tekilochka [14]

Answer: There are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

Explanation:

Given: Mass of urea = 40 g

Number of moles is the mass of substance divided by its molar mass.

First, moles of urea (molar mass = 60 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

So, the number of atoms present in 0.67 moles are as follows.

0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms

In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.

4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms

Thus, we can conclude that there are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

7 0
3 years ago
How many atoms of nitrogen are in Fe2(NO4)2?
djverab [1.8K]

<em>the</em><em> </em><em>number</em><em> of</em><em> </em><em>nitrogen</em><em> </em><em>atoms</em><em> </em><em>in</em><em> </em><em>the </em><em>compound</em><em> </em><em>is</em><em> </em><em>two</em>

5 0
3 years ago
Do moles of any substance have the same number of atoms
love history [14]
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Hope that helps 
7 0
3 years ago
Balance the following equation __N2+__O2→__N2O​
fenix001 [56]

Answer:

2N₂   +  O₂  →  2N₂O

Explanation:

Given equation:

        N₂   +  O₂  →  N₂O

In balancing a chemical equation, the number of atoms on both sides of the expression must be the same.

To solve this problem, we use a simple mathematical approach;

  put coefficients a,b and c

             aN₂   +  bO₂  →  cN₂O  

Conserving N;

                   2a  = 2c

Conserving O:

                  2b  = c

 Let a = 1, c = 1 , b  = \frac{1}{2}

   multiply through by 4

           a = 2, b  = 1 and c  = 2

 Balanced equation is;

          2N₂   +  O₂  →  2N₂O

3 0
3 years ago
7.456 g sample of UF6 is added to water. 6.53 g of a solid containing U, F and O and 1.69 g of a gas are formed. The gas is 5% H
stepan [7]
<span>a. What is the empirical formula of the gas? In this case, the empirical formula is the same as the molecular formula
</span>
An empirical formula is a formula that gives the proportions of the elements present in a certain compound however it does not give the actual numbers or the arrangement of the atoms. To determine this, we do as follows:

H = (1.69)(.05) = 0.08 g ( 1 mol / 1.01 g ) = 0.0792 / 0.0792 = 1
F =  (1.69)(.95) = 1.61 g ( 1 mol / 19 g ) = 0.0847 / 0.0792 = 1

The empirical formula would be HF.

<span>b. What is the molecular formula of the solid?
I bet there is a lacking information for the solid. We cannot determine the molecular formula with only the values given above. The closest would be the compound UF2O2.

</span><span>c. Write a balanced equation for the reaction between UF6 and H2O.
</span>2H2O + UF6 -> UF2O2 +4HF
5 0
3 years ago
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