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2 years ago

if I had 5 toes and 6 toes how many toes will I have NO HINT try your best to get close to the answer give u 105 points

Engineering

2 answers:

SVETLANKA909090 [29]2 years ago

4 0

Answer:

ONE I THANK YEAH CAUSE I'M YOUREEEEEEE SISTERSSSS

Explanation:

Rasek [7]2 years ago

3 0

Answer:

11 toes on one foot? and 5 one the other or just 11 toes?

your NO HINT threw me off

Explanation:

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I'm so confused to this question <br>What is the difference between Science and Engineering?

muminat

Explanation:

Science is the body of knowledge that explores the physical and natural world. Engineering is the application of knowledge in order to design, build and maintain a product or a process that solves a problem and fulfills a need (i.e. a technology).

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2 years ago

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Who plays blox burg? if u do write ur username in commentsSsSS

marusya05 [52]

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A 3.0-m wide rectangular asphalt channel discharges 33.84 m^3/s of water with a depth of 2.0 m. What is the head loss in 100 m l

BaLLatris [955]

Answer:

Head loss in 100 m length equals 1.00 m.

Explanation:

The head loss in an open channel is calculated using manning's equation as follows

$Q=\frac{1}{n}\frac{A^{5/3}}{P^{2/3}}S_{f}^{1/2}$

For a asphalt rectangular channel we have

Area of flow = $3.0\times 2.0 = 6m^{2}$

Wetted Perimeter = $3.0+2\times 2.0=7.0m$

manning's roughness coefficient = 0.016

Applying values in the above equation we get

$33.84=\frac{1}{0.016}\times \frac{6^{5/3}}{7^{2/3}}S_{f}^{1/2}\\\\\therefore S^{1/2}_{f}=0.1\\\\\therefore S_{f}=0.01$

Now we know that

$S_{f}=\frac{H_{L}}{L}\\\\\therefore H_{l}=0.01\times 100m=1.00m$

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3 years ago

A diagonal aluminum alloy tension rod of diameter d and initial length l is used in a rectangular frame to prevent collapse. The

Ksenya-84 [330]

Answer:

$\Delta L = 0.1883 inch$

Explanation:

Given data:

d = 0.5 inch

$L_i = 8 ft$

$\sigma_{allow} = 20 kpsi$

we know that change in length is given as

$\Delta L = \frac{PL}{AE}$

$= \frac{P}{A}\times \frac{L}{E}$

$= \sigma_{allow} \times \frac{L}{E}$

modulus of elasticity E for aluminium alloy is $10.2 \times 10^6 psi = 10.2 \times 10^3 kpsi$

$\Delta L = \frac{20 \times 8}{10.2\times 10^3}$

$\Delta L = 0.01569 ft$

$\Delta L = 0.1883 inch$

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2 years ago

Guys answer this pop quiz question it’s a joke btw it not real:) anyways here the pop quiz ok (Am walking my dog and the leashe

mash [69]

Answer:

I think its b if you get it right tell me or no

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3 years ago