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Alenkasestr [34]
3 years ago
5

Assume that television broadcasts are nonrival and nonexcludable (some TV stations, such as those on cable TV, are excludable, b

ut many are not) and that there are no live TV recording devices, such as VCRs or DVRs like TiVo. How can advertising solve the free‑rider problem?

Engineering
2 answers:
Archy [21]3 years ago
8 0

Answer:

Advertising acts in a method similar to a fee. People who watch TV broadcasts must watch ADs. TV stations turn this into money by selling airtime to advertisers.

Explanation:

A non-rival good is a good whose consumption by one person does not reduce the remaining quantity available. An example is a street light.For non-excludable goods, it is impossible to prevent everyone from enjoying the benefits of the good. An example is a lighthouse. This is where the free rider problem comes in.A free rider is someone enjoying the benefits of a good without paying for it.  When a good is both non-rival and non-excludable, it is convenient for consumers to enjoy the benefit without paying for it.If TV broadcasts are both non-rival and non-excludable, everybody can choose to become a free rider. Advertising can solve this problem by converting free riders to potential buyers of goods or services advertised during broadcasts. This way, stations can generate revenue by selling airtime.

ryzh [129]3 years ago
3 0

Answer: Advertising acts in a method similar to a fee. People who watch TV broadcasts must watch ADs. TV stations turn this into money by selling airtime to advertisers.

Explanation:

A non-rival good is a good whose consumption by one person does not reduce the remaining quantity available. An example is a street light.

For non-excludable goods, it is impossible to prevent everyone from enjoying the benefits of the good. An example is a lighthouse. This is where the free rider problem comes in.

A free rider is someone enjoying the benefits of a good without paying for it.  When a good is both non-rival and non-excludable, it is convenient for consumers to enjoy the benefit without paying for it.

If TV broadcasts are both non-rival and non-excludable, everybody can choose to become a free rider. Advertising can solve this problem by converting free riders to potential buyers of goods or services advertised during broadcasts. This way, stations can generate revenue by selling airtime.

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Write a matrix, that is a lower triangular matrix.
shepuryov [24]

Answer:

\left[\begin{array}{ccc}10&0&0\\14&25&0\\57&18&39\end{array}\right]

Explanation:

A lower triangular matrix is one whose elements above the main diagonal are zero meanwhile all the main diagonals elements and below are nonzero elements. This is one of  the two existing types of triangular matrixes. Attached you will find a image referring more about triangular matrixes.

If there is any question, just let me know.

6 0
3 years ago
Which of these processes uses a die and a press to form parts?
Irina-Kira [14]

The process of die forming that uses a die and a press to form parts from the given processes is called; C: Hydroforming

<h3>What are some of the steps in the die forming operations?</h3>

There are different types of die forming in sheet metal operations. Now, Hydroforming is a specialized type of die forming that uses a high pressure hydraulic fluid to press room temperature working material into a die.

Tailor Welding is a process of making welded blanks made from individual sheets of steel of different thickness, strength and even coating that are joined together by the use of laser welding.

Read more about Welding operations at; brainly.com/question/9450571

4 0
2 years ago
Some_____
Thepotemich [5.8K]

Answer:

it’s IGS

Explanation:

because i read

5 0
3 years ago
What is the resistance of a resistor if the current flowing through it is 3mA and the voltage across it is 5.3V?
Flura [38]

Answer: 1766.667 Ω = 1.767kΩ

Explanation:

V=iR

where V is voltage in Volts (V), i is current in Amps (A), and R is resistance in Ohms(Ω).

3mA = 0.003 A

Rearranging the equation, we get

R=V/i

Now we are solving for resistance. Plug in 0.003 A and 5.3 V.

R = 5.3 / 0.003

= 1766.6667 Ω

= 1.7666667 kΩ

The 6s are repeating so round off to whichever value you need for exactness.

6 0
1 year ago
4. What are these parts commonly called?
patriot [66]

These parts are commonly called carburetor emulsion tubes. These tubes maintain the air-fuel ratio at different speeds.

The carburetor is a device of the combustion engine power supply system that mixes fuel and air in order to facilitate internal combustion.

The carburetor emulsion tubes are tubes that maintain the air-fuel ratio at different velocities.

These tubes (carburetor emulsion tubes) are small brass cylinders where the metering needle slides into them.

Learn more about carburetors here:

brainly.com/question/4237015

7 0
3 years ago
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