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snow_tiger [21]
3 years ago
11

The image shows the relative positions of Earth and the Sun for each of the four seasons. Earth travels in an elliptical orbit a

nd is about two million miles closer to the Sun in the winter than in the summer.(DOK 2)
Engineering
2 answers:
vovangra [49]3 years ago
7 0

Answer:

you didn't attach the image hun..

Explanation:

Zigmanuir [339]3 years ago
6 0

Answer:

You didn't attach the image.

You might be interested in
PLS HELP
RSB [31]

Answer:

T=kg·m^2/s^2

Explanation:

T = kg (m^2/s^2) m^3 /m^3

Here I wrote down the unit for every dimension.

T=kg m^2 / s^2

m^3 is divided between m^3, this is equal to 1.

Result: T=kg·m^2/s^2

PD: I'm not sure if this is what you ask for. I hope it helps

4 0
3 years ago
Design a logic circuit that has a 4-bit binary number as an input and one output. The output should be 1 iffthe input is a prime
Maurinko [17]

Answer:

Check the explanation

Explanation:

Solution

Let the L_1 binary input one A,B,C,D and output is F with L_1 binary inputs we have 16=2^4 combination as in below.

Kindly check the attached image below to get the full step by step explanation to the question above.

5 0
4 years ago
The toughness of a material does what, when it's been heated?​
Sindrei [870]
It melt making it easily malleable
6 0
3 years ago
2.5 kg of air at 150 kPa and 12°C is contained in a gas-tight, frictionless piston-cylinder device. The air is now compressed to
Korolek [52]

Answer:

Work input =283.47 KJ

Explanation:

Given that

P_1=150\ KPa

P_2=600\ KPa

T=12°C=285 K

m= 2.5 kg

Given that this is the constant temperature process.

e know that work for isothermal process  

W=P_1V_1\ln \dfrac{P_1}{P_2}

W=mRT\ln \dfrac{P_1}{P_2}

So now putting the values

W=mRT\ln \dfrac{P_1}{P_2}

W=2.5\times 0.287\times 285\ln \dfrac{150}{600}

W=-283.47 KJ

Negative sign indicates that work is done on the system.

So work input =283.47 KJ

8 0
3 years ago
A piston-cylinder assembly contains 2 lb of air at a temperature of 540 degrees R and a pressure of 1 atm. The air is compressed
attashe74 [19]

Answer:

W=-123.8Btu

Explanation:

Hello,

In this problem, the piston-cylinder assembly make us state the energy balance as:

Q-W=\Delta U

Thus, we must now compute \Delta U in terms of Cv as follows:

\Delta U=mCv(T_2-T_1)\\\Delta U=2lb*0.173\frac{Btu}{lb*R}*(840R-540R)\\ \Delta U=103.8Btu

Now, since heat is given off, its sign is negative, thus, the work is computed as:

W=Q-\Delta U\\W=-20Btu-103.8Btu=-123.8Btu

This work means that work was done over the system in order to allow the compression.

The suppositions were:

- The change in the internal energy is a function of the temperature.

- Air is an ideal gas.

Best regards.

8 0
4 years ago
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