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Anni [7]
4 years ago
8

An incident ray traveling in a slower medium strikes a boundary with a faster medium. What happens when its angle of incidence i

s greater than the critical angle?
Physics
2 answers:
inn [45]4 years ago
3 0
The phenomenon that is observed when an incident ray travelling in a slower medium strikes the boundary of a faster medium with an angle greater than the critical angle is known as total internal reflection.
Total internal reflection results in the the ray being reflected within the medium, instead of leaving it after undergoing diffraction. This phenomenon is the working principle of optical fibers. 
olganol [36]4 years ago
3 0

Answer: There is total internal reflction in the faster medium

Explanation:

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I hope that helps!
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The type of graph that would most appropriately display Sarah's data is a line graph.

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What is Newton's law of universal gravitation?
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Describe all the ways that newtons laws can apply in a car crash
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7 0
3 years ago
A rocket blasts off vertically from rest on the launch pad with an upward acceleration of 2.90 m/s2 . At 20.0s after blastoff, t
Brilliant_brown [7]

Answer:

A) 580m

B) 0 m/s

C) 9.8m/s^2

D) downward

E) 10.87s

F) 106.62 m/s

Explanation:

A) The distance traveled by the rocket is calculated by using the following expression:

y=\frac{1}{2}at^2

a: acceleration of the rocket = 2.90 m/s^2

t: time of the flight = 20.0 s

y=\frac{1}{2}(2.90\frac{m}{s^2})(20.0s)^2=580m

B) In the highest point the rocket has a velocity with magnitude zero v = 0m/s because there the rocket stops.

C) The engines of the rocket suddenly fails in the highest point. There, the acceleration of the rocket is due to the gravitational force, that is 9.8 m/s^2

D) The acceleration points downward

E) The time the rocket takes to return to the ground is given by:

t=\sqrt{\frac{2y}{g}}=\sqrt{\frac{2(580m)}{9.8m/s^2}}=10.87s

10.87 seconds

F) The velocity just before the rocket arrives to the ground is:

v=\sqrt{2gy}=\sqrt{2(9.8m/s ^2)(580m)}=106.62\frac{m}{s}

6 0
3 years ago
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