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Cloud [144]
2 years ago
14

Melanie and Mark borrowed $2500 at a simple interest rate of 7% for a period of 3 years. What was the interest?

Mathematics
1 answer:
natima [27]2 years ago
3 0

Answer:

525 $

Step-by-step explanation:

Amount borrowed = $2500

Rate = 7%

Time = 3 years

therefor interest = $2500 X 7/100 X 3

     Hope it help You

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Explain how the words term and coefficient are used in talking about the algebraic expression.
cupoosta [38]
<h2><u>Answer:</u></h2>

The <u>algebraic expressions</u> are composed of several elements: Terms, Coefficients, Signs, Variables and Exponents. In this case we will focus on the first two.

<u>The terms</u> are composed of sign, coefficient, variable and exponent. The terms are separated from each other by the plus sign (+) or the minus sign (-).

For example, in the following expression:

2x-3x

We have two terms separated by the negative sign (-):

2x is the first term

-3x is the second term

Now, <u>the coefficients</u> are the numbers that multiply the variable. <u>Note that if this coefficient is one (1) it is omitted .</u>

For example in the following expression, the variable is x:

2x-3x+x

2 is the coefficient of x in the first term

-3 is the coefficient of x in the second term

1 is the coefficient of x in the third term, <u>but is omitted </u>


In order to understand this in a better way, see the figure attached, where the algebraic expression is composed by one term.

6 0
3 years ago
Is the given number a solution of an equation or inequality 3x-4=10;5
kotykmax [81]

The given number is not a solution of the equation i.e. the number is an inequality

<h3>How to determine the solution?</h3>

The equation is given as:

3x- 4 = 10

The number is given as:

5

This means that

x = 5

Substitute x = 5 in 3x- 4 = 10

3 * 5- 4 = 10

Evaluate the product

15- 4 = 10

Evaluate the difference

11 = 10

The above equation is not true i.e. the equation is actually an inequality

Hence, the given number is not a solution of the equation i.e. the number is an inequality

Read more about inequality at

brainly.com/question/24372553

#SPJ1

7 0
2 years ago
44cm is rounded to nearest whole cm. Write down the maximum possible length it could have been.
sesenic [268]

Answer:

44.49 repeated

Step-by-step explanation:

Sorry for the wait

8 0
3 years ago
A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.
irakobra [83]

Answer:

The integral is equal to 5\sec^2(2x)+C for an arbitrary constant C.

Step-by-step explanation:

a) If u=\tan(2x) then du=2\sec^2(2x)dx so the integral becomes \int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C. (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case u=\sec(2x) hence du=2\tan(2x)\sec(2x)dx. We rewrite the integral as \int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C.

c) We use the trigonometric identity \tan(2x)^2+1=\sec(2x)^2 is part b). The value of the integral is 5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C. which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.  

3 0
3 years ago
Divide. Write the quotient in lowest terms, 1 1/3 divided by 1 3/4. Please give a thorough explanation as i need help to figure
GaryK [48]

Answer:

Step-by-step explanation:

convert mixed fractions to improper fractions

rule=a b/c=(ac+b)/c

(1 1/3)/(1 3/4)

(4/3)/(7/4)

rule for dividing fractions=(a/b)/(c/d)=(a/b)(d/c)

(4/3)(4/7) then you can multiply the numerators and denominators

16/21

7 0
3 years ago
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