Answer:
Explanation:
Given
Force=18lb
extension=8in
Using Hooke's law to get the spring constant(k)
F=ke
Then,
K=f/e
K=18/8
K=2.25lb/in
Work done by spring is given by
W=1/2Fe
Or W=1/2ke²
Then,
Work done in stretching the spring to 14in
W=1/2ke²
W=0.5×2.25×14²
W=220.5lbin
1 Inch-pounds Force to Joules = 0.113J
Then, to joules
W=0.133×220.5
W=29.33J
To solve this problem it is necessary to apply the concepts related to conservation of the moment.
By definition for the particular case we have to,
Where,
Mass first skater
Speed of first skater
Velocity of second skater
Our values are given as,
Replacing in our equation and re-arrange to find
The mass from the second skater is 35.85Kg
Answer:
110.4 v
Explanation:
Find the equivalent resistance of the two parallel circuits
R1 and R2 in parallel = R1 * R2 / (R1+ R2) = <u>1 ohm </u>
similarly R4 and R5 = <u>4.77 ohms</u>
Now you can add the three resistances into one (R3=10)
1 ohm + 10 ohm + 4.77 ohm = 15.77 ohms
Now
V = IR
V = 7 amps * 15.77 ohm = 110.4 v
Please see the solution in the attached drawing.
Read it from the top down.
If you ever come back again, with one that has
an AC source and an L or a C in the circuit, I'll
be looking for more than 5 points for that one. :-)