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Lesechka [4]
3 years ago
7

Please help!!Show the electronic configuration of magnesium atom​.

Chemistry
2 answers:
ch4aika [34]3 years ago
6 0

Answer:

Neon

[He]2s²2p⁶

Explanation:

just search that and u will see it -_-

Galina-37 [17]3 years ago
3 0

Explanation:

Magnesium has atomic number 12. It will be distributed in K, L, M shell in the following way:

K shell can accommodate a maximum of 2 electrons.

L shell can accommodate a maximum of 8 electrons and

M shell will accommodate 2 electrons

So the configuration becomes 2, 8,3

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State the aufbau principle.
Inessa05 [86]

Answer:

Explanation:

To show the sequence of electrons filling sublevels in an atom, the Aufbau's principle is one of the tenets that must be satisfied to write a proper notation.

  • Aufbau's principle states that "the sublevels with lower energies are filled up before those with higher energies".
  • Note that based on this principle, we are not inferring that sublevels are filled in numerical order.
  • The patter of filling is shown below:

         1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f e.t.c

5 0
3 years ago
Cu+2AgNO
baherus [9]

Answer:

Mass of Ag produced = 64.6 g

Note: the question is, how many grams of Ag is produced from 19.0 g of Cu and 125 g of AgNO3

Explanation:

Equation of the reaction:

Cu + 2AgNO3 ---> 2Ag + Cu(NO3)2

From the equation above, 1 mole of Cu reacts with 2 moles of AgNO3 to produce 2 moles of Ag and 1 mole of Cu(NO3)2.

Molar mass of the reactants and products are; Cu = 63.5 g/mol, Ag = 108 g/mol, AgNO3 = 170 g/mol, Cu(NO3)2 = 187.5 g/mol

To determine, the limiting reactant;

63.5 g of Cu reacts with 170 * 2 g of AgNO3,

19 g of Cu will react with (340 * 19)/63.5 g of AgNO3 =101.7 g of AgNO3.

Since there are 125 g of AgNO3 available for reaction, it is in excess and Cu is the limiting reactant.

63.5 g of Cu reacts to produce 108 * 2 g of Ag,

19 g of Cu will react to produce (216 * 19)/63.5 g of Ag = 64.6 g of Ag.

Therefore mass of Ag produced = 64.6g

6 0
4 years ago
Enter your answer in the provided box. Sodium stearate (C17H35COONa) is a major component of bar soap. The Ka of the stearic aci
kogti [31]

Answer:

11.61 is the pH of 10.0 mL of a solution containing 3.96 g of sodium stearate.

Explanation:

Concentration of sodium stearate acid : c

Moles of sodium stearate = \frac{3.96 g}{306 g/mol}=0.01294 mol

Volume of the solution = 10.0 mL = 0.010 L

c=\frac{0.01294 mol}{0.010 L}=1.294 M

C_{17}H_{35}COONa\rightleftharpoons C_{17}H_{35}COO^-+Na^+

[C_{17}H_{35}COO^-]=c=1.294 M

C_{17}H_{35}COO^-+H_2O\rightleftharpoons C_{17}H_{35}COOH +OH^-

initially c

c           0    0

At equilibrium

(c-x)       x    x

Dissociation constant of an acid = K_a=1.3\times 10^{-5}

Expression of a dissociation constant of an acid is given by:  

K_a=\frac{[C_{17}H_{35}COOH][OH^-]}{[C_{17}H_{35}COO^-]}

K_a=\frac{(x)^2\times x}{(c -x)}

1.3\times 10^{-5}=\frac{x^2}{1.294-x}

Solving for x;

x = 0.0041 M

[OH^-]=0.0041 M

The pOH of the solution:

pOH=-\log[OH^-]=-\log[0.0041 M]=2.39

pH = 14 -pOH

pH = 14 - 2.39 = 11.61

11.61 is the pH of 10.0 mL of a solution containing 3.96 g of sodium stearate.

7 0
4 years ago
Which statement best describes the amount of catalyst that remains at the end of a reaction?
Ivenika [448]
I believe the correct answer is C. The amount of catalyst is the same at the end as at the beginning of the reaction. Catalysts can't be consumed by the reaction thus is not D.
7 0
3 years ago
Read 2 more answers
What is the number of protons, neutrons and electrons in Mg2+
VARVARA [1.3K]
This ion has 12 protons,12 neutrons and 10 electrons because the element lost 2 electrons and turned to a positive ion
3 0
3 years ago
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