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morpeh [17]
3 years ago
10

Your teacher created a 2 g/L salt-water solution (solution A) and a 2.5 g/L salt-water solution (solution B), both in 500 mL of

water. Using the concentration equation, which solution is more concentrated? How do you know?
Chemistry
1 answer:
Genrish500 [490]3 years ago
3 0

solution B is concentrated

Explanation:

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Calcium nitrate reacts with sodium phosphate to form sodium nitrate and calcium phosphate. Given 96.1 grams of calcium nitrate w
Bingel [31]
Equation is:

Ca(NO3)2 + Na3PO4 —> NaNO3 + Ca3(PO4)2

Balance it out

3Ca(NO3)2 + 2Na3PO4 —> 6NaNO3 + Ca3(PO4)2

You have 96.1g of Calcium Nitrate

Moles = Mass/Molar Mass

Molar mass of Calcium Nitrate is 164.088 g/mol

96.1g / 164.088 g/mol =0.586 moles

Mole ratio is 3:1

Therefore 0.586/3 moles of calcium phosphate

Moles x molar mass = mass

0.586/3 x 310.18 g/mol = 60.6~g roughly as theoretical yield
5 0
3 years ago
Consider the electrolysis of molten barium chloride, BaCl2. (a) Write the half-reactions. (b) How many grams of barium metal can
Zielflug [23.3K]

Answer: a)  Cathode(-): Ba^+^2+2e^-\rightarrow Ba

Anode(+): 2Cl^-\rightarrow Cl_2+2e^-

b) 0.640 grams of Ba will be deposited.

Explanation:  a) The problem is based on Faraday law of electrolysis. Molten barium chloride has Ba^+^2 ion and Cl^- ion. Barium ion is reduced and chloride is oxidized. Reduction takes place at cathode and oxidation at anode. So, the half reactions will be:

Cathode(-): Ba^+^2+2e^-\rightarrow Ba

Anode(+): 2Cl^-\rightarrow Cl_2+2e^-

b) The question asks, how many grams of barium metal can be produced by supplying 0.50 ampere for 30 minutes.

From the Cathode half-reaction, 1 mole of Ba is deposited by 2 moles of electrons and we know that 1 mole of electron carries one Faraday that is 96485 Coulomb.

Coulombs for 2 moles of electrons will be = 2*96485 C = 192970 C

So, we can say that, 192970 C will deposit 1 mole of Ba metal.

Total available coulombs can be calculated using the formula:

q=i*t

where, q is electric charge in coulomb, i is current in ampere and t is time in seconds.

q=q=0.50A*30min(\frac{60sec}{1min})

q = 900 C         (note: 1 C = 1 A*sec)

Let's calculate how many moles of Ba will get deposited by 900 C.

900C(\frac{1molBa}{192970C})

= 0.00466 mole Ba

Convert the moles of Ba to grams and for this we multiply by molar mass of Ba which is 137.33 gram per mol.

0.00466molBa(\frac{137.33g}{1mol})

= 0.640 g Ba

So, 0.50 A for 30 minutes will deposit 0.640 grams of Ba metal.

6 0
2 years ago
Which is a series circuit and a parallel circuit
kirza4 [7]

Explanation:

A is a series circuit

B is parallel circuit

8 0
3 years ago
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This element has 3 electrons in its Lewis dot structure and is in the 3p orbital section.
Lynna [10]
The answer is Al. If it is a main group element with 3 electrons in its Lewis dot structure, it must be in group 3A. If it is in the 3p orbital section, then it must be in period 3, since the p orbital is a valence orbital and the number that preceeds it is the principal quantum number. Therefore, your answer is the element in period 3 and group 3A, which is aluminum.
3 0
2 years ago
Who hypothesized that electrons orbit around a nucleus? Bohr Greek philosophers Thomson Dalton
makvit [3.9K]

The answer to this question is bohr Greek


4 0
3 years ago
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