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3 years ago

Which statement is the correct representation of these electric field lines?

Physics

2 answers:

GuDViN [60]3 years ago

4 0

I would say a. hope this helps

soldi70 [24.7K]3 years ago

4 0

Answer

The correct answer is "Plate A is negatively charged and plate B is positively charged"

Explanation:

In an electric field, the direction depends on the charge of the plate.

For a positively charged plate, the electric field is always directed away from it.

For the negatively charged plate, the electric field will be directed towards it.

Looking ate plate A, the electric field in directing toward it. Therefore, it's a negative charge.

For plate B, the electric field is moving away from it, making it a positively charged plate.

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a car travels at 15 m/s for 10 s. It then speeds up with a constant acceleration of 2.0 m/s? for 15 s. At the end of this time,

Firlakuza [10]

V = u + at where u is initial velocity (15 m/s), a is acceleration (2m/s^2) and t is time (15 seconds)

V = 15 + 2 X 15

V = 45 m/s

6 0

3 years ago

The flywheel of an engine has moment of inertia 2.50 kg m2 about its rotation axis. What constant torque is required to bring it

MrRissso [65]

Answer:

Explanation:

From the question we are told that

The moment of inertia is $I = 2.50 \ kg \cdot m^2$

The final angular speed is $w_f = 400 rev/min = \frac{400 * 2\pi}{60} = 41.89 \ rad/s$

The time taken is $t = 8.0 s$

The initial angular speed is $w_i = 0\ rad/s$

Generally the average angular acceleration is mathematically represented as

$\alpha = \frac{w_f - w_i }{t}$

=> $\alpha = \frac{41.89}{8}$

=> $\alpha = 5.24 \ rad/s^2$

Generally the torque is mathematically represented as

$\tau = I * \alpha$

=> $\tau = 5.24 * 2.50$

=> $\tau = 13.09 \ N \cdot m$

5 0

3 years ago

Find the instantaneous velocity at 1 s . can anyone help with c-h!!!

Lelu [443]

Rise over run at 1 second
It’s the same slope from 0 to 2 seconds
10/2=5mps
As a note all time points between 0and 2 will have this instantaneous velocity

Instantaneous velocity at time 2 is 0

7 0

3 years ago

A string under a tension of 68 N is used to whirl a rock in a horizontal circle of radius 3.7 m at a speed of 16.53 m/s. The str

alekssr [168]

Answer:

$F = 5253.7 N$

Explanation:

As we know that tension force in the string will be equal to the centripetal force on the string

so we will have

$T = \frac{mv^2}{L}$

now we have

$68 = \frac{m(16.53^2)}{3.7}$

now we have

$68 = 73.8 m$

$m = 0.92 kg$

now when string length is 0.896 m and its speed is 71.5 m/s then we will have

$F = \frac{mv^2}{r}$

$F = \frac{0.92(71.5^2)}{0.896}$

$F = 5253.7 N$

8 0

3 years ago

Read 2 more answers

Which is the resulting direction of a surface wave

Sliva [168]

In a surface wave (like water) the water goes up and down, but the wave travels across (parallel to) the surface.

3 0

3 years ago