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3 years ago

7

Which statement is the correct representation of these electric field lines?

2 answers:

GuDViN [60]3 years ago

4 0

I would say a. hope this helps

soldi70 [24.7K]3 years ago

4 0

Answer

The correct answer is "Plate A is negatively charged and plate B is positively charged"

Explanation:

In an electric field, the direction depends on the charge of the plate.

For a positively charged plate, the electric field is always directed away from it.

For the negatively charged plate, the electric field will be directed towards it.

Looking ate plate A, the electric field in directing toward it. Therefore, it's a negative charge.

For plate B, the electric field is moving away from it, making it a positively charged plate.

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A man jogs at a speed of 1.6 m/s. His dog waits 1.8 s and then takes off running at a speed of 3 m/s to catch the man. How far w

inessss [21]

Answer:

The dog catches up with the man 6.1714m later.

Explanation:

The first thing to take into account is the speed formula. It is $v=\frac{d}{t}$ , where v is speed, d is distance and t is time. From this formula, we can get the distance formula by finding d, it is $d=v\cdot t$

Now, the distance equation for the man would be:

$d_{man}=v_{man}\cdot t=1.6\cdot t$

The distance equation for the dog would be obtained by the same way with just a little detail. The dog takes off running 1.8s after the man did. So, in the equation we must subtract 1.8 from t.

$d_{dog}=v_{dog}\cdot (t-1.8)=3\cdot (t-1.8)$

For a better understanding, at t=1.8 the dog must be in d=0. Let's verify:

$d_{dog}=v_{dog}\cdot (1.8-1.8)=3\cdot (0)=0$

Now, for finding how far they have each traveled when the dog catches up with the man we must match the equations of each one.

$d_{man}=d_{dog}$

$1.6\cdot t=3\cdot (t-1.8)$

$1.6\cdot t=3\cdot t-5.4$

$1.4\cdot t=5.4$

$t=\frac{5.4}{1.4}$

$t=3.8571s$

The result obtained previously means that the dog catches up with the man 3.8571s after the man started running.

That value is used in the man's distance equation.

$d_{man}=1.6\cdot t=1.6\cdot (3.8571)$

$d_{man}=6.1714m$

Finally, the dog catches up with the man 6.1714m later.

6 0

3 years ago

What Do You Already Know about Density? Material Design. Number each material and sort the items in order from lowest (1) to hig

Elena-2011 [213]

Answer:

1. Dry Beans - 591.75 kg/m^3

2. Flour - 593 kg/m^3

3. Wax - 900 kg/m^3

4. Wet sand - 2039 kg/m^3

5. Chalk - 2499 kg/m^3

6. Talcum Powder - 2776 kg/m^3

7. Copper - 8960 kg/m^3

Explanation:

Make sure your units are the same

7 0

3 years ago

How many significant digits are measurement 0.00210 mg?

jek_recluse [69]

There are 3 significant figures, if that answers the question.

8 0

3 years ago

Read 2 more answers

A projectile is launched at an angle of 60 degrees to the horizontal at an initial speed of 10 meters per second. What is the ma

Flura [38]

Answer:

5 sq. root 3

Explanation:

theta= 60°

=> u sin theta = 10 × sin 60

= 10× sq. root 3/2

= 5 sq. root 3

3 0

3 years ago

Read 2 more answers

Astronaut Rob leaves Earth in a spaceship at a speed of 0.960c relative to an observer on Earth. Rob's destination is a star sys

olchik [2.2K]

Answer:

A) 15.0 years

Explanation:

Due to the distance to the star system is in light-year units, we can compute the time by using:

$t=\frac{d}{v}=\frac{14.4 l-y}{0.960}=15l-y$

then, Rob will take to complete the trip about 15 light-years.

hope this helps!!

7 0

3 years ago