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ehidna [41]
3 years ago
15

Write the equation which links gravitational field strength,gravitational potential energy,height and mass

Physics
1 answer:
Andru [333]3 years ago
8 0

Answer:

PE = mgh

Explanation:

PE is potential energy

m is mass

g is gravitational field strength

h is height

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The resistivity of gold is 2.44 × 10-8 Ω · m at room temperature. A gold wire that is 1.8 mm in diameter and 11 cm long carries
tester [92]
Power in a wire where current is flowing can be calculated from the product of the square of the current and the resistance. Resistance is equal to the product of resistivity and length divided by the area of the wire. We do as follows:

Resistance  =  2.44 × 10-8 ( 0.11) / (π)(0.0009)^2 = 1.055x10^-3 <span>Ω

P = I^2R = .170^2 (</span>1.055x10^-3 ) = 3.048x10^-5 W
6 0
3 years ago
Explain why, if you go to the moon, your weight would change but your mass wouldnt
Evgen [1.6K]
There's little gravity so your weight would change but not your mass
3 0
3 years ago
Compare the current in the 8-ohm resistors to the current in the 4-ohm resistors.
Gemiola [76]

Answer:

a)   i₈ = 0.5 i₄,  b)   i₁₀ = 0.3 i₃,    i₁₀ = 0.8 i₈

Explanation:

For this exercise we use ohm's law

       V = i R

        i = V / R

we assume that the applied voltage is the same in all cases

let's find the current for each resistance

         

R = 4 Ω

         i₄ = V / 4

R = 8 Ω

         i₈ = V / 8

we look for the relationship between these two currents

         i₈ /i₄ = 4/8 = ½

         i₈ = 0.5 i₄

R = 3 Ω

        i₃ = V3

R = 10 Ω

         

        i₁₀ = V / 10

   

we look for relationships

       i₁₀ / 1₃ = 3/10

       i₁₀ = 0.3 i₃

       i₁₀ / 1₈ = 8/10

       i₁₀ = 0.8 i₈

7 0
2 years ago
Please help<br> Right answers please<br> Will mark brainliest
balandron [24]

Answer:

a. 45 N. / b. 0.08 m/s^2. / c. 102 N

F = ma

F = 15(3)

F = 45 newtons

F/m = a

20/250 = a

0.08 m/s^2 = a

R = ma

R =1.5(68)

102 N

3 0
3 years ago
The length of the mercury thread is found to be 4cm and 24cm at ice point and steam point respectively on an ungraduated thermom
BabaBlast [244]

Answer:

The difference between ice and steam in Celsius (Centigrade) is 100 deg.

So the difference between and 4 cm and 24 cm of the thread corresponds to 100 deg C.

So 8 cm is 4 cm greater than the ice point

4 cm / 20 cm = 1/5     since the steam point and the ice point are 20 cm apart

Then 1/5 * 100  deg C = 20 deg C   the requested temperature

6 0
3 years ago
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