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Anarel [89]
3 years ago
12

Coach purchased footballs and basketballs from two different stores.

Mathematics
1 answer:
Serjik [45]3 years ago
4 0

Answer:

  • $6.25

Step-by-step explanation:

Let football cost be f and basketball cost be b

<u>We have two equations as per given:</u>

  • 5f + 14b = 110
  • 10f + 6b = 82.50

We need to find b, therefore we'll eliminate f

<u>To do so we'll double the first equation and subtract the second one:</u>

  • 2(5f + 14b) - (10f + 6b) = 2(110) - 82.50
  • 28b - 6b = 220 - 82.50
  • 22b = 137.5
  • b = 137.5/22
  • b = 6.25

Each basketball costs $6.25

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How do I solve this, and what is the answer? please and thank you.
vovangra [49]

Answer:

A. (x +8) + (-4x+31)/(x^2+2x+1)

Step-by-step explanation:

When you perform long division of polynomials, the first quotient term is the ratio of the highest-degree terms in the numerator and denominator: x^3/x^2 = x.

This fact eliminates all but choices A and C.

The denominator of the remainder term is the denominator of the original expression, so will be x^2 +2x +1, as shown in choice A.

__

So, simply based on a couple of facts about long division (that you learned in the early elementary grades), you can make the correct choice of answer without actually working the problem in detail.

_____

This is a polynomial long division problem. It is worked in virtually the same way that numerical long division problems are worked: first you find a quotient term, then you multiply that by the divisor and subtract the result from the dividend. The difference is the new dividend. These steps are identical to numerical long division.

For polynomial long division, instead of lining up the digits with the same place value, you line up the terms with the same degree of the variable.

As mentioned above, the quotient term is computed only from the highest-degree terms of dividend and divisor, so that part is actually simpler than for numerical long division.

A dividend that is of lower degree than the divisor is considered to be the remainder. As with numerical long division, it can be expressed as a fraction with the divisor as the denominator.

Numerical example: 18/7 = 2 remainder 4 or 2 4/7.

8 0
3 years ago
Trigonometry questions
trasher [3.6K]

We'll use standard labeling of right triangle ABC, C=90 degrees, legs a, b, hypotenuse c.

11.

Right triangle, cliff peak A, boat B, angle opposite cliff is B=28.9 deg. adjacent leg a=65.7 m, cliff height is leg b.

tan B = b/a

b = a tan B = 65.7 tan 28.9° = 36.3 m

12.

Similar story, boat at B, opposite b=3.5 m, rope c=12 m

sin B = b/c

B = arcsin b/c = arcsin (3.5/12) = 17.0°

13.

c=124 m, A=58°

sin A = a/c

a = c sin A = 124 sin 58 = 105.2 m

14.

That's a hypotenuse c=4-1.2 = 2.8 m to a height b=1.8m so

cos A = b/c

A = arccos b/c = arccos (1.8/2.8) = 50.0°

15.

Not a right triangle, an isosceles triangle.  Half of it is a right triangle with hypotenuse one arm, c=9.8 cm and angle opposite half the base of B=62/2=31°.  We're after d=2b:

sin B = b/c

b = c sin B

d = 2b = 2 c sin B = 2(9.8) sin 31 = 10.1 cm

Almost equilateral


4 0
3 years ago
Because of high production-changeover time and costs, a director of manufacturing must convince management that a proposed manuf
7nadin3 [17]

Answer:

See explanation below

Step-by-step explanation:

Here, a director of manufacturing must convince management that a proposed manufacturing method reduces costs before the new method can be implemented. The current production method operates with a mean cost of $220 per hour.

a) The alternative and null hypotheses would be:

H0: μ ≥ 220

Ha: μ < 220

b) Comment on the conclusion when H0 cannot be rejected:

When we fail to reject the null hypothesis H0, there is not enough evidence to conclude that the mean cost can be reduced from $220. Therefore the manager's proposed method cannot be implemented.

c) Comment on the conclusion when H0 can be rejected:

When the null hypothesis, H0 is rejected, there is enough evidence to conclude that the mean cost can be reduced from from $220. Therefore the manager's proposed method can be implemented.

3 0
3 years ago
Micheal is 5 years older than Rui Feng and Vishal is thrice as old as Micheal if Rui Feng is p years old, find i) Michael's pres
Kitty [74]

Answer:

Michael's present age = p + 5

Michael's present age = 3p + 15

Sum of there ages 6 year age = 5p + 38

Sum of there ages 3 year ago = 5p - 11

Step-by-step explanation:

Assume;

Age of Rui Feng = x

Age of Micheal = x + 5

Age if Vishal = 3[x+5]

Given:

Age of Rui Feng = P

Computation:

Michael's present age = Age of Rui Feng + 5

Michael's present age = p + 5

Vishal's present age = 3[p + 5]

Michael's present age = 3p + 15

Sum of there ages 6 year age = [p + 6] + [p + 5 + 6] + 3[p + 5] + 6

Sum of there ages 6 year age = 5p + 38

Sum of there ages 3 year ago = [p - 3] + [p + 5 - 3] + 3[p + 5] - 3

Sum of there ages 3 year ago = 5p - 11

8 0
3 years ago
A 3cm×10cm rectangle sits inside a circle with radius of 12. Find the area of the shaded region
kolezko [41]

Answer:

422.4cm²

Step-by-step explanation:

area of circle is pi x 12² which is 144 pi

144pi subtract 30 is 422.4

6 0
3 years ago
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