Answer:a) P = Po + rho×h×g
b) P = 5.4 × 10^9 pa
c) F = P/A = (Po + rho×h×g)/A
d) 1.174×10^11N
Explanation: Using the formula
P = Po + rho×h×g
P = 1.0 x 10^5 + 1000 × 5.5 × 9.81
P = 5.4 × 10^9pa
The magnitude of the force exerted by water on the top of the person's head F at the depth h in terms of P
F = P/A = (Po + rho×h×g)/A
Using the above formula
Where A = 0.046m^2
F = P/ A = 5.4×10^9/0.046
F = 1.174×10^11N
Answer: The minimum acceleration for the air plane is 2.269m/s2.
Explanation: To solve such problem the equation of motion are applicable.
The initial velocity is 0 since the airplane was initially standing. We are going to use this equation
V^2=U^2+2as
33^2=0+2a (240)
a= 2.269m/s2
Answer:
<h2>
14.66secs</h2>
Explanation:
Given the formula for calculating the depth in metres expressed as
depth in meters = ½ (1500 m/sec × Echo travel time in seconds)
Given depth of the challenger = 10, 994 meters, we will substitute this given value into the formula given to calculate the time take for the echo to travel.
10, 994 = depth in meters = ½ * 1500 m/sec × Echo travel time in seconds
10,994 = 750 * Echo travel time in seconds
Dividing both sides by 750;
Echo travel time in seconds = 10,994 /750
Echo travel time in seconds ≈ 14.66secs (to two decimal places)
Therefore, it would take an echo sounder’s ping 14.66secs to make the trip from a ship to the Challenger Deep and back
Its vey True trust me on this when I say it is
Answer:
the weight of alien is 200 newtons
Explanation:
The computation of the alien weight is shown below:
Given that
Acceleration = 20m/sec^2
And, the mass is 10 kg
So, the weight of alien is
= 20 × 10
= 200 newtons
hence, the weight of alien is 200 newtons
