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3 years ago

This is an opinion question but

1 answer:

8 0

AJAJAJAJ I just going to say what ever I think it is important because imagine you see a rock and think is a normal rock but it ends up being really rare and you can make a lot of money out of it

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A motorcycle traveling south reaches a speed of 38.0 m/s. It then begins uniform negative acceleration and comes to rest after 7

Aleonysh [2.5K]

Answer: 30.641

Explanation: If you get the ave which is 38.0 then the vi which is 7.359

38.0-7.359=30.641/0.0 which is 30.641

6 0

3 years ago

Which part of a laser printer applies a positive charge to the paper that attracts the toner particles to it

Shalnov [3]

The part of laser printer that applies a positive charge to the paper in order to attract the toner particles is known as transfer roller.

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What is a laser printer:

A laser printer is a kind of printer that uses the electrostatic digital printing process to perform printing. It makes use of the static electricity and toner powder in place of liquid ink.

The toner is applied to specific areas which are dependent on the charge difference created or on the static electricity.

Following are the components of a laser printer:

Scanning unit:

This unit of a laser printer generally consists of a laser diode, a

scanning motor and a polygon mirror.
It also consists of two-beam alignment lenses.

Cartridge unit:

This unit of laser printer consists of three drums, namely primary

charging roller (PCR), organic photoconductive drum (OPC) , and

image transfer roller (ITR).
The transfer roller is also present at a close vicinity of the

printer's toner cartridge.

Fuser assembly unit:

This unit of laser printer consists of a pressure roller and a fuser roller, where the fuser roller assembly consists of a heating

element.

Therefore, the transfer roller unit of a laser printer applies a positive charge to the paper that attracts the toner particles to it.

Learn more about laser printers here:

<u>brainly.com/question/5039703</u>

#SPJ4

6 0

2 years ago

13. An object with a mass of 2.0 kg has a force of 4.0 newtons applied to it.

julsineya [31]

Answer:2m/s²

Explanation: Well F=MA so sice F=4N and M=2kg let's plug in the values

4N=2KG*A

A=4N/2KG

A=2m/s²

7 0

4 years ago

Calcula el valor de la velocidad de las ondas sonoras en el agua sabiendo que su

dybincka [34]

La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.
La longitud de onda de las ondas sonoras es 1,470 metros.

1) Inicialmente, debemos determinar la velocidad de las ondas sonoras a través del agua ( $v$ ), en metros por segundo:

$v = \sqrt{\frac{K}{\rho} }$ (1)

Donde:

$K$ - Módulo de compresibilidad, en newtons por metro cuadrado.
$\rho$ - Densidad del agua, en kilogramos por metro cúbico.

Si sabemos que $\rho = 1\times 10^{3}\,\frac{kg}{m^{3}}$ y $K = 2,16\times 10^{9}\,\frac{N}{m^{2}}$ , entonces la velocidad de las ondas sonoras es:

$v = \sqrt{\frac{2,16\times 10^{9}\,\frac{N}{m^{2}}}{1\times 10^{3}\,\frac{kg}{m^{3}} } }$

$v\approx 1469,694\,\frac{m}{s}$

La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.

2) Luego, determinamos la longitud de onda ( $\lambda$ ), en metros, mediante la siguiente fórmula:

$\lambda = \frac{v}{f}$ (2)

Donde $f$ es la frecuencia de las ondas sonoras, en hertz.

Si sabemos que $v\approx 1469,694\,\frac{m}{s}$ y $f = 1000\,hz$ , entonces la longitud de onda de las ondas sonoras es:

$\lambda = \frac{1469,694\,\frac{m}{s} }{1000\,hz}$

$\lambda = 1,470\,m$

La longitud de onda de las ondas sonoras es 1,470 metros.

Para aprender más sobre las ondas sonoras, invitamos a ver esta pregunta verificada: brainly.com/question/1070238

6 0

2 years ago

Describe the motion for each segment below. Include start position, relative speed, and direction. Then calculate the speed of e

ratelena [41]

Where is the picture?

3 0

3 years ago