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ryzh [129]
3 years ago
6

A sheet of standard U.S. typing paper measures 8.50 in by 11 in. What is its area in square centimeters? (Area =L x W)

Mathematics
2 answers:
jekas [21]3 years ago
7 0

Answer:

the area would be 935cm

Step-by-step explanation:

ty for reading :P

igomit [66]3 years ago
6 0

603.2246 square centimeters.

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I need help on number 3 on my math homework sheet and it's 8,376+blank=45,791 please help me I'm so stuck bye now
lakkis [162]
The answer is:  37,415 .
__________________________________
GIven: 8,376 + ________ = 45,791 ;  
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 → Solve for what goes in the blank.
____________________________________________________________
 You would subtract "8,376" from "45,791" to get the answer:
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 → 45,791 − 8,376 = 37,415 ;    → which is the answer.
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5 0
3 years ago
Triangle ABC is a right triangle.
mina [271]

Answer:

They are complementary.

Step-by-step explanation:

we know that

The sum of the interior angles of a triangle must be equal to 180 degrees

so

A+B+C=180°

where

A,B and C are the measures of the interior angles of triangle

In a right triangle

The measure of angle C ( I assume that the right angle is C) is equal to 90 degrees

so

A+B+90°=180°

A+B=180°-90°

A+B=90°

Remember that

If two angles are complementary, then their sum is equal to 90 degrees

therefore

A and B are complementary angles

3 0
3 years ago
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What is the area of a rectangle that has lenghts of 2/5 foot and 3/8
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0.15 as fraction or multiply 3/8 and 2/5
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arsen [322]
(-1,8) is the correct answer I’m pretty sure
5 0
3 years ago
Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers
slamgirl [31]

Answer:

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

Step-by-step explanation:

Let be \vec u = (2,-3), its unit vector is determined by following expression:

\hat {u} = \frac{\vec u}{\|\vec u \|}

Where \|\vec u \| is the norm of \vec u, which is found by Pythagorean Theorem:

\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}

\|\vec u\| = \sqrt{13}

Then, the unit vector is:

\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)

\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right)

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

6 0
3 years ago
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