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Ratling [72]
3 years ago
13

Plz help with good answer dont answer saying "I think or " im sorry"

Mathematics
1 answer:
STatiana [176]3 years ago
5 0

r= 9 because 45/5 is 9 and it works the same way for the rest of the problems.

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Could someone please help
myrzilka [38]
19 x 4 is the equation and the answers is 76
8 0
3 years ago
Read 2 more answers
Forty-five roses, plus some number of daffodils and tulips, are blooming in a garden.
stellarik [79]

The maximum number of of bouquets the gardener could have made is 3

<h3>How to find unknown parameter</h3>

Total = 45

let

  • number of daffodils = x
  • number of tulips = y

Roses = 4x

Tulips = 4x + 15

Total = roses + daffodils + tulips

45 = 4x + x + (4x + 15)

45 = 5x + 4x + 15

45 = 9x + 15

45 - 15 = 9x

30 = 9x

x = 30/9

x = 3.33333333333333

Approximately,

x = 3

Let more about equation:

brainly.com/question/16863577

4 0
2 years ago
Find the value of y.<br> Please help asap. I've been on this for ages.
anastassius [24]

Answer:

53.50

Step-by-step explanation:

168 is the circumference so i divided it by pi (3.14)

5 0
3 years ago
What is the product?<br><br> (5.63 x 10^5) x 5,600,000
victus00 [196]

Answer: 3.1528 \times 10^{12}.


Step-by-step explanation: Given expression (5.63 \times 10^5) \times 5,600,000.

In order to find the product of given expression, we need to convert 5,600,000 into scientific notation, because other number is also in scientific notation.

5,600,000 = 5.6 × 10^6.

Therefore, (5.63 \times 10^5) \times 5,600,000 =(5.63 \times 10^5) \times (5.6 \times 10^6).

Now, multiplying 5.63 × 5.6 first, we get 31.528.

And 10^5 × 10^6 = 10^11.

Therefore,

(5.63 \times 10^5) \times (5.6 \times 10^6) = 31.528 \times 10^11.

<h3>Or 3.1528 × 10^12.</h3>

6 0
3 years ago
Find the value of c so that (x+2) is a factor of the polynomial<br><br> p(x)=3x^4-x^2+cx-2
DedPeter [7]
Using polynomial long division, we get
         
         3x^3+6x^2+11x
         _____________
(x+2) | 3x^4-x^2+cx-2
          -(3x^4+6x^3)
          ____________
             6x^3-x^2+cx-2
          - (6x^3+12x^2)
         _____________
        11x^2+cx-2
      -(11x^2+22x) 
       __________
        (22+c)x-2. 

If you're wondering how I did the long division, what I essentially did was get the first value (at the start, it was 3x^4) and divided it by the first value of the divisor (which in x+2 was x) to get 3x^3 in our example. I then subtracted the polynomial by the whole divisor multiplied by, for example, 3x^3 and repeated the process.

For this to be a perfect factor, (x+2)*something must be equal to (22+c)x-2. Focusing on how to cancel out the 2, we have to add 2 to it. To add 2 to it, we have to multiply (x+2) by 1. However, there's a catch, which is that we subtract whatever we multiply (x+2) by, so we have to multiply it by -1 instead. We still need to cross out (22+c)x. Multiplying (x+2) by -1, we get
(-x-2) but by subtracting the whole thing from something means that we have to add -(-x-2)=x+2 to something to get 0. x+2-x-2=0, xo (22+c)x-2 must equal -x-2, meaning that (22+c)=-1 and c=-23
4 0
3 years ago
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