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nadezda [96]
3 years ago
10

Choose the way that machine may change force... Doc Below

Physics
2 answers:
Serhud [2]3 years ago
7 0

fjfjfj

Explanation:

rufifiriirifieif

Katyanochek1 [597]3 years ago
7 0

Answer:it’s all of the above for the ck-12

Explanation:

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A machine is applying a torque to rotationally accelerate a metal disk during a manufacturing process. An engineer is using a gr
Viefleur [7K]

Explanation:

Question 9 A machine is applying a torque to rotationally accelerate a metal disk during a manufacturing process. An engineer is using a graph of torque as a function of time to determine how much the disk's angular speed increases during the process The graph of torque as a function of time starts at an initial torque value and is a straight line with positive slope. What aspect of the graph and possibly other quantities must be used to calculate how much the disk's angular speed increases during the process? The slope of the graph multiplied by the disk's radius will equal the change in angular speed The area under the graph multiplied by the disk's radius will equal the change in angular speed. The slope of the graph divided by the disk's rotational inertia will equal the change in angular speed. The area under the graph divided by the disk's rotational inertia will equal the change in angular speed. The area under the graph multiplied by the disk's rotational inertia will equal the change in angular speed E

8 0
3 years ago
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Your go-cart breaks down right before the end of a race, so you have to push it over the finish line. The go-cart has a mass of
Flura [38]

a) W=mg=833 N by definition

b) F=ma=76.5 N according to Newton's second law

c) a=F/m=4.12 m/s^2

d) m=F/a=720/5.5=130.91 kg

6 0
3 years ago
An initially motionless test car is accelerated to 115 km/h in 8.58 s before striking a simulated deer. The car is in contact wi
hoa [83]

Answer:

a)       a = 3.72 m / s², b)    a = -18.75 m / s²

Explanation:

a) Let's use kinematics to find the acceleration before the collision

             v = v₀ + at

as part of rest the v₀ = 0

             a = v / t

Let's reduce the magnitudes to the SI system

              v = 115 km / h (1000 m / 1km) (1h / 3600s)

              v = 31.94 m / s

              v₂ = 60 km / h = 16.66 m / s

l

et's calculate

             a = 31.94 / 8.58

             a = 3.72 m / s²

b) For the operational average during the collision let's use the relationship between momentum and momentum

            I = Δp

            F Δt = m v_f - m v₀

            F = \frac{m ( v_f - v_o)}{t}

            F = m [16.66 - 31.94] / 0.815

            F = m (-18.75)

Having the force let's use Newton's second law

            F = m a

            -18.75 m = m a

             a = -18.75 m / s²

4 0
3 years ago
German physicist Werner Heisenberg related the uncertainty of an object's position ( Δ x ) to the uncertainty in its velocity (
Ierofanga [76]

Answer:

The uncertainty in the position of the electron is 5.79x10^{-9}m

Explanation:

The Heisenberg uncertainty principle is defined as:

\Lambda p\Lambda x ≥ \frac{h}{4 \pi}  (1)

Where \Lambda p is the uncertainty in momentum, \Lambda x is the uncertainty in position and h is the Planck's constant.

The momentum is defined as:

p =mv  (2)

Therefore, equation 2 can be replaced in equation 1

\Lambda (mv) \Lambda x ≥ \frac{h}{4 \pi}

Since, the mass of the electron is constant, v will be the one with an associated uncertainty.

m \Lambda v \Lambda x ≥ \frac{h}{4 \pi} (3)

Then, \Lambda x can be isolated from equation 3

\Lambda x ≥ \frac{h}{m \Lambda v 4 \pi}  (4)

\Lambda x = \frac{6.626x10^{-34}J.s}{(9.11x10^{-31} kg)(0.01x10^{6}m/s) 4 \pi}

But 1J = Kg.m^{2}/s^{2}

\Lambda x = \frac{(6.624x10^{-34} Kg.m^{2}/s^{2}.s)}{(9.11x10^{-31} kg)(0.01x10^{6}m/s) (4 \pi)}

\Lambda x = 5.79x10^{-9}m

Hence, the uncertainty in the position of the electron is  5.79x10^{-9}m

7 0
3 years ago
Please please help me please please help please please
Alborosie

Answer:

Refraction

The rainbow is created because the index of refraction of water droplets changes as a function of wavelength. So, when the light enters the water droplet different colors will bend at different angles thus producing a dispersive effect known as a rainbow.

6 0
3 years ago
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