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Dafna1 [17]
3 years ago
8

The north pole is in the middle of the ocean. A person at sea level at the north pole would be 3,949 miles from the center of Ea

rth. The sea floor below the north pole is at an elevation of approximately -2.7 miles. The elevation of the south pole is about 1.7 miles. How far is a person standing on the south pole from a submarine at the sea floor below the north pole?
Mathematics
2 answers:
Lynna [10]3 years ago
7 0
HOOIIIIIIIIIIIIIIIIII
damaskus [11]3 years ago
3 0

Answer:

I LOVE YOU

Step-by-step explanation:

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If f(x) and 1(x) are inverse functions of each other and f(x) = 2x+5, what is ri(8)?
Yakvenalex [24]

Answer:

3/2

Step-by-step explanation:

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The oblique pyramid has a square base with an edge length of 5 cm. The height of the pyramid is 7 cm. What is the volume of the
ExtremeBDS [4]
The answer is <span>58 cm3
</span>
The volume of the pyramid with square base is:
V = s² * h / 3
s - the edge length, s = 5 cm
h - height, h = 7 cm

V = 5² * 7 / 3
V = 25 * 7 / 3
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3 years ago
How do we use the Pythagoras theorem in "everyday life".
DochEvi [55]
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3 years ago
How do you do this question?
IRINA_888 [86]

Answer:

.

Step-by-step explanation:

6 0
3 years ago
Write the equation of the line that is parallel to the given segment and that passes through the point (-3,0).
grandymaker [24]

Answer:

Option (B)

Step-by-step explanation:

In the figure attached,

A straight line is passing through two points (0, 2) and (3, 1).

Slope of this line (m_1) = \frac{y_2-y_1}{x_2-x_1}

                                   = \frac{2-1}{0-3}

                                   = -\frac{1}{3}

Let the slope of a parallel to the line given in the graph = m_2

By the property of parallel lines,

m_1=m_2

m_2=-\frac{1}{3}

Equation of a line passing through a point (x', y') and slope 'm' is,

y - y' = m(x - x')

Therefore, equation of the parallel line which passes through (-3, 0) and having slope = -\frac{1}{3} will be,

y-0=-\frac{1}{3}(x+3)

y=-\frac{1}{3}x-1

Option (B). will be the answer.

5 0
3 years ago
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