Question

The perimeter of a rectangle is 256 inches. How long are the sides if the length exceeds the width by 16 inches? Mark lets x represent the width of the rectangle and writes the equation 2x + 2(x + 16) = 256. Solving for x, the width of the rectangle is

Answer 1

2x + 2x + 32 = 256

-32

2x+2x = 224

4x=224

/4

x= 56





lenght = width+16

perimeter = width + width + (width + 16) + (width + 16)

perimeter = x + x + (x+16) + (x+16)

perimeter = 2x + 2((x+16)



therefore width = 56 
length = 72