Answer:
B. It would lead to an increase of global temperatures.
Explanation:
Gas burns when it is hot. Therefore the more gas that our cars consume, the hotter the air will be when the car releases those gas vapors. Causing the air to become hotter.
Hope this helped <3 :) brainliest?
Answer:
V₁ = 10 mL
Explanation:
Given data:
Initial volume of HCl = ?
Initial molarity = 3.0 M
Final molarity = 0.10 M
Final volume = 300.0 mL
Solution:
Formula:
M₁V₁ = M₂V₂
M₁ = Initial molarity
V₁ = Initial volume of HCl
M₂ =Final molarity
V₂ = Final volume
Now we will put the values.
3.0 M ×V₁ = 0.10 M×300.0 mL
3.0 M ×V₁ = 30 M.mL
V₁ = 30 M.mL /3.0 M
V₁ = 10 mL
Answer:
It's not correct. For balancing, we need to put the coefficients in the molecule, not in the athom. Because if you do this, you're creating another molecule, instead of a balacing, for which the reaction may not happen - but anyway, it would be another reaction.
The correct balacing is:
2NaOH + 1H2S → 1Na2S + 2H2O
Explanation:
Look: Na2OH does not even exist. OH has only one free link, so he can't - in normal conditions - make another one with any athom. That's why we should write 2NaOH instead of Na2OH. The first means "2 mols of NaOH".
Answer:
C. Work and time
Explanation:
Power is the rate work is done, so this would involve how long it would take to do a certain amount of Work and it is also the measure of the transfer of energy over a period of time.
The formula for power is:
Where:
P = Power
W = Work
t = time
Answer:
n = 3
l = 1
ml = +1
ms = +1/2
Es paramagnético
Explanation:
Siguiendo las reglas de llenado de orbitales, los 17 electrones del cloro se llenan así:
1S = <u>⇅</u>
2S = <u>⇅</u>
2P = <u>⇅</u> <u>⇅</u> <u>⇅</u>
3S = <u>⇅</u>
3P = <u>⇅</u> <u>⇅</u> <u>↑</u>
<u />
El número cuántico principal n, es el nivel energético donde se encuentra este electrón:
n = 3 (Porque está en el orbital 3P
El número cuántico secundario, l, para el orbital 3P es = 1:
l = 1
El número cuántico magnético, ml, es determinado por la posición del electrón. Como está en el tercer orbital 3P:
ml = +1
Y el número cuántico de spin, ms (↑ = +1/2; ↓ = -1/2)=
ms = +1/2
Dado que el último electrón se encuentra desapareado, el cloro es paramagnético dado que el espín de el último electrón no tiene su electrón complementario haciendo que este compuesto pueda interactuar con un campo magnético.
