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solong [7]
3 years ago
6

Determinar los números cuánticos del electrón desapareado en el átomo del cloro (Z = 17) y diga si es paramagnético

Chemistry
1 answer:
Musya8 [376]3 years ago
3 0

Answer:

n = 3

l = 1

ml = +1

ms = +1/2

Es paramagnético

Explanation:

Siguiendo las reglas de llenado de orbitales, los 17 electrones del cloro se llenan así:

1S = <u>⇅</u>

2S = <u>⇅</u>

2P = <u>⇅</u> <u>⇅</u> <u>⇅</u>

3S = <u>⇅</u>

3P = <u>⇅</u> <u>⇅</u> <u>↑</u>

<u />

El número cuántico principal n, es el nivel energético donde se encuentra este electrón:

n = 3 (Porque está en el orbital 3P

El número cuántico secundario, l, para el orbital 3P es  = 1:

l = 1

El número cuántico magnético, ml, es determinado por la posición del electrón. Como está en el tercer orbital 3P:

ml = +1

Y el número cuántico de spin, ms (↑ = +1/2; ↓ = -1/2)=

ms = +1/2

Dado que el último electrón se encuentra desapareado, el cloro es paramagnético dado que el espín de el último electrón no tiene su electrón complementario haciendo que este compuesto pueda interactuar con un campo magnético.

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kogti [31]

Answer:

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Explanation:

Catalysts only facilitate reaction once molecules collide. Increased temperature makes molecules move more, and thus collide more. For concentration, if there are more molecules in the same amount of room/liquid, there will be more collisions because there are more of the molecules to collide.

8 0
3 years ago
3. How much energy is needed to raise 45 grams of water from 40°C to 115 °C?
Dafna1 [17]

Answer:

Q = 114349.5 J

Explanation:

Hello there!

In this case, since this a problem in which we need to calculate the total heat of the described process, it turns out convenient to calculate it in three steps; the first one, associated to the heating of the liquid water from 40 °C to 100 °C, next the vaporization of liquid water to steam at constant 100 °C and finally the heating of steam from 100 °C to 115 °C. In such a way, we calculate each heat as shown below:

Q_1=45g*4.18\frac{J}{g\°C}*(100\°C-40\°C)=11286J\\\\Q_2=45g* 2260 \frac{J}{g} =101700J\\\\Q_3=45*2.02\frac{J}{g\°C}*(115\°C-100\°C)=1363.5J

Thus, the total energy turns out to be:

Q_T=11286J+101700J+1363.5J\\\\Q_T=114349.5J

Best regards!

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The metal zirconium becomes superconducting at temperatures below 3.4000K.
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-269.75 degrees Celsius

Explanation:

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The ratio of sizes between the ionic radii of anions and cations in a cell has no influence on the manner of packing for that ce
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Answer:

The answer is B. False

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The ratio of sizes between the ionic radii of cations and anions in a cell influences the manner of packing for that cell thereby predicting the possible cation/anion coordination number in any compound and establishing the structure of ionic solids.

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<h3>What is the rate of chemical reaction?</h3>

The rate of a chemical reaction refer to the rate of change in concentration of the reaction over the change in time. Introduction.

When you double the concentration the rate doubles. The rate is proportional to the square of the concentration of a reactant. When the rate is doubled the concentration rate goes up four times. The rate is not affected by the concentration of a reactant.

Learn more about rate of chemical reaction here.

brainly.com/question/24795637

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