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Anarel [89]
3 years ago
13

9. Which of the following would increase the

Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
3 0
I think the answer is C.
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Calculate the volume of the object immersed in the water in the water in the adjoining figur. ​
kirza4 [7]

Answer:

100 cm³

Explanation:

Hi there!

Subtract:

400 cm³ - 300 cm³

= 100 cm³

Therefore, the volume of the object is 100 cm³.

I hope this helps!

5 0
3 years ago
Write down the group numbers for carbon,oxygen,nitrogen and sulphur <br>​
Bess [88]

Answer:

Carbon - 14

Oxygen - 16

Nitrogen - 15

Sulphur - 16

Explanation:

The question above is related to the "Periodic Table of Elements" which shows the proper arrangement of elements in a table. Every element falls on a<em> group/family</em> within the table. Each group has its own number, and the table has a total of<u> 18 groups</u><em> (from left to right). </em>They are classified according to <em>similarities in their characteristics</em>. For example, group 1 is composed of <em>alkali metals</em> while group 2 is composed of<em> alkali earth metals</em>.

5 0
3 years ago
All the chemical ingredients to make slime have a mass of 48 grams after we mix all the ingredients together how much mass will
Alborosie

Answer:

The answer is C. 48 grams

Explanation: If the mass of all the ingredients is 48 grams the that would be your in total answer

5 0
3 years ago
Which of the following is the correct formula to calculate percent by mass? [Mass of solution (g) + mass of solute (g)] × 100 [M
cricket20 [7]

Answer:

Percent by mass is calculated by tihis formula, Mass of solute (g) ÷ mass of solution (g)] × 100.

Explanation:

For example: if you have a solution 45% m/m (mass percentege), you have 45 g of solute in 100 g of solution.

7 0
3 years ago
Read 2 more answers
A scuba diver creates a spherical bubble with a radius of 3.0 cm at a depth of 30.0 m where the total pressure (including atmosp
solong [7]

Answer:

Radius of the bubble reaches the surface of the water = 4.68 cm

Explanation:

We know Ideal gas equation PV = nRT

Since amount of gas and temperature remains constant

so p₁v₁ = p₂v₂

Volume of Spherical bubble with a radius of 3.0 cm

⇒ v₁= \frac{4}{3}\pir^{3}

⇒ v₁ = \frac{4}{3} x 3.14 x (3)^{3}

Pressure at the depth p₁ = 4 atm

Volume of bubble when it reaches the surface of water =  \frac{4}{3}\pir^{3}

Pressure p₂ = 1 atm

      p₁v₁ = p₂v₂

⇒  4 x  \frac{4}{3} x 3.14 x (3)^{3} =  1 x  \frac{4}{3}\pir^{3}

⇒ r = 4.68 cm

7 0
3 years ago
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