Let n be the smallest of these integers. The other two are then n + 2 and n + 4.
"triple of the sum of thrice the third one and twice the first one is equal to 291" is a long-winded way of saying
3 (3 (n + 4) + 2n) = 291
Solve for n :
3 (3n + 12 + 2n) + 291
3 (5n + 12) = 291
15n + 36 = 291
15n = 255
n = 17
Then the greatest of the three integers is n + 4 = 21.
To expand two terms such as these, we can use the method called FOIL (stands for First, Outer, Inner, Last). Here is what I mean:
We have two terms: (x - 2)(x - 1)
We should first multiply the First two terms of each term in order to complete the F stage:
(x)*(x) =

So then, we take the two outer terms and multiply them together to complete the O stage:
(x)*(-1) = -x
So far we have two things that we have calculated; at the end of the FOIL process we will have four.
To keep going with the FOIL, we now multiply the two inner terms to complete the I stage:
(-2)*(x) = -2x
Last but not least, we need to complete the L stage - so we multiply the two last terms of each term:
(-2)*(-1) = 2
Now that we have our four terms, let us add them together and combine like terms:

Since -x and -2x both have the x portion in common and they are added together, we can add them to create one single term:
-x + (-2x) = -3x
So now that we have our terms completed, we can combine into one polynomial equation:

or
Answer:
multiply 9 from m and -3
9m - 27 + 3m = 7m + 43
12m - 27 = 7m + 43
12m - 7m = 43+ 27
5m = 70 cut 70 by 5 in 14 times [ 14 x 5= 70 ]
m = 14 answer ❤️❤️ it is 100% correct now!
Answer:
[ See the attached picture ]
The diagonals of a parallelogram bisect each other.
✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.
✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.
Proof :
♕ And we're done! Hurrayyy! ;)
# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P
☄ Hope I helped! ♡
☃ Let me know if you have any questions! ♪
☂
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