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Bumek [7]
3 years ago
12

What is the value of k? k = 28 k = 29 k = 31 k = 42

Mathematics
2 answers:
julia-pushkina [17]3 years ago
6 0

Answer:

k=29

Step-by-step explanation:

we know that

-------> by supplementary angles

Solve for k

Combine like terms in the left side

Substract  both sides

Divide by  both sides

   

therefore

the answer is the option

B

 

defon3 years ago
3 0
The answer is 29
K is equal to 29
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Given three consecutive odd integers, what is the greatest number if triple of the sum of thrice the third one and twice the fir
Nostrana [21]

Let n be the smallest of these integers. The other two are then n + 2 and n + 4.

"triple of the sum of thrice the third one and twice the first one is equal to 291" is a long-winded way of saying

3 (3 (n + 4) + 2n) = 291

Solve for n :

3 (3n + 12 + 2n) + 291

3 (5n + 12) = 291

15n + 36 = 291

15n = 255

n = 17

Then the greatest of the three integers is n + 4 = 21.

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2 years ago
In Minnesota, the current temperature is 35.7​ o​ F and is dropping 2.5​ o​ F every day. Greenland’s temperature is 25.2​ o​ F a
Anna71 [15]

Answer:

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4 0
3 years ago
Expand (x-2) (x-1). Must be in polynomial form.
Ludmilka [50]
To expand two terms such as these, we can use the method called FOIL (stands for First, Outer, Inner, Last). Here is what I mean:

We have two terms: (x - 2)(x - 1)

We should first multiply the First two terms of each term in order to complete the F stage:

(x)*(x) = x^{2}

So then, we take the two outer terms and multiply them together to complete the O stage:

(x)*(-1) = -x

So far we have two things that we have calculated; at the end of the FOIL process we will have four.

To keep going with the FOIL, we now multiply the two inner terms to complete the I stage:

(-2)*(x) = -2x

Last but not least, we need to complete the L stage - so we multiply the two last terms of each term:

(-2)*(-1) = 2

Now that we have our four terms, let us add them together and combine like terms:

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Since -x and -2x both have the x portion in common and they are added together, we can add them to create one single term:

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6 0
3 years ago
9(m-3)+3m=7m+43 help me please
nikdorinn [45]

Answer:

multiply 9 from m and -3

9m - 27 + 3m = 7m + 43

12m - 27 = 7m + 43

12m - 7m = 43+ 27

5m = 70 cut 70 by 5 in 14 times [ 14 x 5= 70 ]

m = 14 answer ❤️❤️ it is 100% correct now!

6 0
3 years ago
Read 2 more answers
Prove that the diagonals of a parallelogram bisect each other​
Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof :\begin{array}{ |c| c |  c |  } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In  \: \triangle ^{s}  \:AOB \: and \: COD  } \\  \sf{(i)}&  \sf{ \angle \: OAB =  \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\  \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\  \sf{(iii)} &\sf{ \angle \: OBA=  \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\  \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}.          Proved ✔

♕ And we're done! Hurrayyy! ;)

# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P

☄ Hope I helped! ♡

☃ Let me know if you have any questions! ♪

\underbrace{ \overbrace  {\mathfrak{Carry \: On \: Learning}}} ☂

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

5 0
3 years ago
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