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Nana76 [90]
3 years ago
9

... is an actual sequence of interactions (i.e., an instance) describing one specific situation; a ... is a general sequence of

interactions (i.e., a class) describing all possible ... associated with a situation. ... are used as examples and for clarifying details with the client. ... are used as complete descriptions to specify a user task or a set of related system features.
Engineering
1 answer:
Alexandra [31]3 years ago
3 0

Answer:

  1. Scenario
  2. Use case
  3. Scenarios
  4. Scenarios
  5. Use case

Explanation:

A <u>scenario</u> is an actual sequence of interactions (i.e., an instance) describing one specific situation; a <u>use case</u> is a general sequence of interactions (i.e., a class) describing all possible <u>scenarios</u> associated with a situation. <u>Scenarios</u> are used as examples and for clarifying details with the client. <u>Use cases</u> are used as complete descriptions to specify a user task or a set of related system features.

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You work for a printing company, and you realize that your colleague sent incorrect price quotes to a client. You begin to write
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The sentence excerpted from the e-mail uses passive voice.  

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Read 2 more answers
You are riding in an elevator that is going up at 10 ft/s. You are holding your cell phone 5 ft above the floor when it suddenly
Luba_88 [7]

Answer:

It falls at the same speed in both cases.

Explanation:

If I were standing still the phone would be in free fall after slipping out of my hand.

I set a frame of reference with origin on the ground and the positive Y axis pointing up.

It would slip at t0 = 0, from a position Y0 = 5 ft, with a speed of Vy0 = 0.

It would be subject to an gravitational acceleration of -32.2 ft/s^2.

Since acceleration is constant:

Y(t) = Y0 + Vy0 * t + 1/2 * 4 * t^2

When it hits the floor at t1 it will be at Y(t1) = 0

0 = 5 + 0 * t1 - 16.1 * t1^2

16.1 * t1^2 = 5

t1^2 = 5 / 16.1

t1 = \sqrt{0.31} = 0.55 s

If the elevator is standing still it would take 0.55 s to hit the ground.

Now, if the elevator is moving up at 10 ft/s.

The frame of reference will have its origin at the place the floor of the elevator is at t = 0, and stay there as the elevetor moves. The floor of trhe elevator will have a position of Ye = 10 * t

Vy0 = 10 ft/s because it will be moving initially at the same speed as the elevator.

And it will hit the floor of the elevator not at 0, but at

Ye = 10 * t2

So:

10 * t2 = 5 + 10 * t2 - 16.1 * t2^2

0 = 5 - 16.1 * t2^2

16.1 * t1^2 = 5

t1^2 = 5 / 16.1

t1 = \sqrt{0.31} = 0.55 s

It falls at the same speed in both cases.

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3 years ago
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