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Nana76 [90]
3 years ago
9

... is an actual sequence of interactions (i.e., an instance) describing one specific situation; a ... is a general sequence of

interactions (i.e., a class) describing all possible ... associated with a situation. ... are used as examples and for clarifying details with the client. ... are used as complete descriptions to specify a user task or a set of related system features.
Engineering
1 answer:
Alexandra [31]3 years ago
3 0

Answer:

  1. Scenario
  2. Use case
  3. Scenarios
  4. Scenarios
  5. Use case

Explanation:

A <u>scenario</u> is an actual sequence of interactions (i.e., an instance) describing one specific situation; a <u>use case</u> is a general sequence of interactions (i.e., a class) describing all possible <u>scenarios</u> associated with a situation. <u>Scenarios</u> are used as examples and for clarifying details with the client. <u>Use cases</u> are used as complete descriptions to specify a user task or a set of related system features.

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Consider a junction that connects three pipes A, B and C. What can we say about the mass flow rates in each pipe for steady flow
Elis [28]

Answer:

The statement regarding the mass rate of flow is mathematically represented as follows \Rightarrow \rho \times Q_{3}=\rho \times Q_{1}+\rho \times Q_{2}

Explanation:

A junction of 3 pipes with indicated mass rates of flow is indicated in the attached figure

As a basic sense of intuition we know that the mass of the water that is in the pipe junction at any instant of time is conserved as the junction does not accumulate any mass.

The above statement can be mathematically written as

Mass_{Junction}=Constant\\\\\Rightarrow Mass_{in}=Mass_{out}

this is known as equation of conservation of mass / Equation of continuity.

Now we know that in a time 't' the volume that enter's the Junction 'O' is

1) From pipe 1 = V_{1}=Q_{1}\times t

1) From pipe 2 = V_{2}=Q_{2}\times t

Mass leaving the junction 'O' in the same time equals

From pipe 3 = V_{3}=Q_{3}\times t

From the basic relation of density, volume and mass we have

\rho =\frac{mass}{Volume}

Using the above relations in our basic equation of continuity we obtain

\rho \times V_{3}=\rho \times V_{1}+\rho \times V_{2}\\\\Q_{3}\times t=Q_{1}\times t+Q_{2}\times t\\\\\Rightarrow Q_{3}=Q_{1}+Q_{2}

Thus the mass flow rate equation becomes \Rightarrow \rho \times Q_{3}=\rho \times Q_{1}+\rho \times Q_{2}

6 0
4 years ago
When using fall arrest, free fall must be kept at or below how many feet
SashulF [63]
<h3>Answer:</h3>

two feet or less

<h3>Explanation:</h3>

8 0
3 years ago
A dipstick is (a direct,an indirect) measurement device
icang [17]
Direct because it’s going right in the spot it needs to be in
3 0
4 years ago
Vai trò của chủ đầu tư
White raven [17]

Answer:

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4 0
3 years ago
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Calculate the fraction of lattice sites that are Schottky defects for cesium chloride at 573 oC (this temperature is below the m
inn [45]

Answer:

2.9\times 10^{-6}

Explanation:

Q_s = Energy for defect formation = 1.86 eV

T = Temperature = 573^{\circ}\text{C}=573+273.15=846.15\ \text{K}

k = Boltzmann constant = 8.62\times 10^{-5}\ \text{eV/K}

The fraction of lattice sites that are Schottky defects is given by

\dfrac{N_s}{N}=e^{-\dfrac{Q_s}{2kt}}\\\Rightarrow \dfrac{N_s}{N}=e^{-\dfrac{1.86}{2\times 8.62\times 10^{-5}\times 846.15}}\\\Rightarrow \dfrac{N_s}{N}=2.9\times 10^{-6}

The required ratio is 2.9\times 10^{-6}.

6 0
3 years ago
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