Question

How much calcium chloride will react with100mg of soda ash?

Answer 1

Answer:

105mg of calcium chloride $CaCl_{2}$

Explanation:

The molecular formula of calcium chloride is $CaCl_{2}$ and the molecular formula of soda ash is $Na_{2}CO_{3}$

First of all you should write the balanced reaction between both compounds, so:

$CaCl_{2}+Na_{2}CO_{3}=2NaCl+CaCO_{3}$

Then you should have the molar mass of the two compounds:

Molar mass of $CaCl_{2}=110.98\frac{g}{mol}$

Molar mass of $Na_{2}CO_{3}=105.98\frac{g}{mol}$

Now with stoichiometry you can find the mass of calcium chloride that reacts with 100mg of soda ash, so:

$100mgNa_{2}CO_{3}*\frac{1molNa_{2}CO_{3}}{105.98gNa_{2}CO_{3}}*\frac{1molCaCl_{2}}{1molNa_{2}CO_{3}}*\frac{110.98gCaCl_{2}}{1molCaCl_{2}}=105mgCaCl_{2}$