1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ahrayia [7]
3 years ago
11

How much calcium chloride will react with100mg of soda ash?

Engineering
1 answer:
mixer [17]3 years ago
6 0

Answer:

105mg of calcium chloride CaCl_{2}

Explanation:

The molecular formula of calcium chloride is CaCl_{2} and the molecular formula of soda ash is Na_{2}CO_{3}

First of all you should write the balanced reaction between both compounds, so:

CaCl_{2}+Na_{2}CO_{3}=2NaCl+CaCO_{3}

Then you should have the molar mass of the two compounds:

Molar mass of CaCl_{2}=110.98\frac{g}{mol}

Molar mass of Na_{2}CO_{3}=105.98\frac{g}{mol}

Now with stoichiometry you can find the mass of calcium chloride that reacts with 100mg of soda ash, so:

100mgNa_{2}CO_{3}*\frac{1molNa_{2}CO_{3}}{105.98gNa_{2}CO_{3}}*\frac{1molCaCl_{2}}{1molNa_{2}CO_{3}}*\frac{110.98gCaCl_{2}}{1molCaCl_{2}}=105mgCaCl_{2}

You might be interested in
Which step in the engineering design phase is requiring concussion prevention from blows up to 40 mph an example of?
Charra [1.4K]

Answer:

Target your customers

Explanation:

took the test :)

6 0
3 years ago
Select the best answer to the questo
Norma-Jean [14]

Answer:

C

Explanation:

7 0
3 years ago
Read 2 more answers
Write the following decorators and apply them to a single function (applying multiple decorators to a single function): 1. The f
natita [175]

Answer:

Complete question is:

write the following decorators and apply them to a single function (applying multiple decorators to a single function):

1. The first decorator is called strong and has an inner function called wrapper. The purpose of this decorator is to add the html tags of <strong> and </strong> to the argument of the decorator. The return value of the wrapper should look like: return “<strong>” + func() + “</strong>”

2. The decorator will return the wrapper per usual.

3. The second decorator is called emphasis and has an inner function called wrapper. The purpose of this decorator is to add the html tags of <em> and </em> to the argument of the decorator similar to step 1. The return value of the wrapper should look like: return “<em>” + func() + “</em>.

4. Use the greetings() function in problem 1 as the decorated function that simply prints “Hello”.

5. Apply both decorators (by @ operator to greetings()).

6. Invoke the greetings() function and capture the result.

Code :

def strong_decorator(func):

def func_wrapper(name):

return "<strong>{0}</strong>".format(func(name))

return func_wrapper

def em_decorator(func):

def func_wrapper(name):

return "<em>{0}</em>".format(func(name))

return func_wrapper

@strong_decorator

@em_decorator

def Greetings(name):

return "{0}".format(name)

print(Greetings("Hello"))

Explanation:

5 0
3 years ago
what do we call a landslide in which fine-grained soil moves cohesively but with extensive internal shearing?
pogonyaev
It is called an earth flow
5 0
2 years ago
The electron concentration in silicon at T = 300 K is given by
puteri [66]

Answer:

E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m

Explanation:

From the question we are told that:

Temperature of silicon T=300k

Electron concentration n(x)=10^{16}\exp (\frac{-x}{18})

                                        \frac{dn}{dx}=(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})

Electron diffusion coefficient is Dn = 25cm^2/s \approx 2.5*10^{-3}

Electron mobility is \mu n = 960 cm^2/V-s \approx0.096m/V

Electron current density Jn = -40 A/cm^2 \approx -40*10^{4}A/m^2

Generally the equation for the semiconductor is mathematically given by

Jn=qb_n\frac{dn}{dx}+nq \mu E

Therefore

-40*10^{4}=1.6*10^{-19} *(2.5*10^{-3})*(10^{16} *(\frac{-1}{16})\exp\frac{-x}{16})+(10^{16}\exp (\frac{-x}{18}))*1.6*10^{-19}*0.096* E

E=\frac{-2.5*10^-^7 exp(\frac{-x}{18})+40*10^{4}}{1.536*10^-4exp(\frac{-x}{18} )}

E=1.44*10^-7-2.6exp(\frac{-x}{18} )v/m

7 0
2 years ago
Other questions:
  • A circuit-switching scenario in whichNcs users, each requiring a bandwidth of 25 Mbps, must share a link of capacity 150 Mbps.
    12·1 answer
  • How does fouling affects the performance of a heat exchanger?
    6·1 answer
  • What are cars manufactured with today that allows for quick stopping without the brakes locking up?
    5·1 answer
  • Why is a building considered a type of system?
    6·1 answer
  • What are the causes of electric shock​
    13·1 answer
  • A worker standing on a freshly mopped floor is
    7·1 answer
  • Harmony in music is characterized by _____.
    14·2 answers
  • QUESTIONS
    12·1 answer
  • 1. Asphyxiation is a hazard posed by Compressed Natural Gas (CNG) vehicles and can be detected when you notice
    7·1 answer
  • Which of the following is NOT a true statement about construction drawings?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!