I believe gamma decay but i may be wrong
Answer:
a)
, b)
, c) D. The magnitud of the change in the ball's momentum.
Explanation:
a) The magnitude of the change in the ball's momentum is:
![\Delta p = (0.275\,kg)\cdot \left[\left(1.63\,\frac{m}{s} \right)-\left(-3.28\,\frac{m}{s} \right)\right]](https://tex.z-dn.net/?f=%5CDelta%20p%20%3D%20%280.275%5C%2Ckg%29%5Ccdot%20%5Cleft%5B%5Cleft%281.63%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%29-%5Cleft%28-3.28%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%29%5Cright%5D)

b) The change in the magnitude of the ball's momentum:
![\Delta p' = (0.275\,kg)\cdot \left[(1.63\,\frac{m}{s} )-(3.28\,\frac{m}{s} ) \right]](https://tex.z-dn.net/?f=%5CDelta%20p%27%20%3D%20%280.275%5C%2Ckg%29%5Ccdot%20%5Cleft%5B%281.63%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29-%283.28%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%20%5Cright%5D)

c) The magnitude of the change in the ball's momentum is more directly related to the net force acting on the ball, as it measures the effect of the force on change in ball's motion at measured time according to the Impact Theorem. So, the right answer is option D.
Answer:
The best single equation in order to fin the acceleration is

Explanation:
The best single equation in order to find the acceleration is the following kinematics equation:

As the rocket start from the rest, the initial velocity value is zero. Then the acceleration value is:
