Answer:
The levels of carbon dioxide (CO2) in the atmosphere are reduced
Explanation:
Tectonic uplift refers to the process by which the surface of the earth slowly rises either due to increasing upward force applied from the plates below the surface or decreasing downward force or weight of objects like melting glaciers acting from above. During uplift, land, as well as the sea floor rises forming mountains, plateaus and volcanic Islands.
During the process of weathering, carbon dioxide present in air combines with rainwater and forms carbonic acid. This acidic rainwater then falls on uplifted mountains and rocks weathering them in the process. Minerals present in the rock such as calcium, magnesium and sodium then combine with bicarbonate ions to form carbonates such as calcium carbonate, magnesium carbonate which are found in shells of living and dead organisms and also form rocks such as limestone. In this way, carbon dioxide is removed from the atmosphere.
The correct answer is industrial smog. This type of smog exists in coal power plants which creates smoke and sulfur dioxide which may mix with fog creating a thick blanket of haze. Sulfur dioxide is one primary component of an industrial smog.
Answer:
Barium and Calcium
Explanation:
When heated with chlorine,
Both calcium and barium are able to form ionic bonds.
Hydrogen can only form bonds that are partial positive. It is not strong enough to be considered an ionic bond.
Silicon forms strong covalent with chlorine, called silicon tetrachloride. The structure is in diamond form which requires a lot of heat energy to break the bonds are way more than energy needed to break the bonds between calcium chloride.
Krypton is an inert element which does not form bonds with any elements under standard conditions
Answer:
-88.66 kJ/mol
Explanation:
The expressions of heat capacity (Cp,m) for C(s) and for H₂(g) are:
C(s): Cp,m/(J K-1 mol-1) = 16.86 + (4.77T/10³) - (8.54x10⁵/T²)
H₂(g): Cp,m/(J K-1 mol-1) = 27.28 + (3.26T/10³) + (0.50x10⁵/T²)
Cp = A + BT + CT⁻²
For the Kirchoff's Law:
ΔHf = ΔH°f + 
Where ΔH°f is the enthalpy at 298 K, T1 is 298 K, T2 is the temperature given (373 K), and DCp is the variation of Cp (products less reactants). ΔH°f for ethene is -84.68 kJ/mol and the reaction is:
2C(s) + 3H₂(g) → C₂H₆
So, DCp:
dA = A(C₂H₆) - [2xA(C) + 3xA(H₂)] = 14.73 - [2x16.86 + 3x27.28] = -100.83
dB = B(C₂H₆) - [2xB(C) + 3xB(H₂)] = 0.1272 - [2x4.77x10⁻³ + 3x3.26x10⁻³] = 0.10788
dC = C(C₂H₆) - [2xC(C) + 3xC(H₂)] = 0 - (2x(-8.54x10⁵) + 3x0.50x10⁵) = 15.58x10⁵
dCp = -100.83 + 0.10788T + 15.58x10⁵T⁻²
= -3796.48 J/mol = -3.80 kJ/mol (solved by a graphic calculator)
ΔHf = -84.68 - 3.80
ΔHf = -88.66 kJ/mol
Answer:
The change in concentration of H+ ions is -9.99×10⁻⁵
Explanation:
When pH rises, we talk about neutralization and, there is a decline in proton's concentration.
pH lower than 7 is acid
pH higher than 7 is basic
Protons are neutralized by hydroxides to make water as this:
H₃O⁺ + OH⁻ ⇄ H₂O
pH = - log [H₃O⁺]
[H₃O⁺] = 10^-pH
In conclussion: [H₃O⁺]₁ = 10⁻⁴ → 1×10⁻⁴
[H₃O⁺]₂ = 10⁻⁷ → 1×10⁻⁷
1×10⁻⁷- 1×10⁻⁴
The change in concentration of H+ ions is -9.99×10⁻⁵
