Molar mass is the mass of each element multiplied by subscript, then added together.
So, we’ll do
C = 12g x 12 = 144 g
H = 1g x 22 = 22 g
O = 16g x 11 = 176 g
The total of all of these is the molar mass: 342 g in a mol
The amount of mols of each element in each compound is likely equal to its subscripts.
C = 12 mols
H = 22 mols
O = 11 mols
For the atoms, you’ll multiply each one of the above by Avogadro’s number
Avogadro’s Number: 6.02 x 10^23 atoms/mol
True
After the process of Ore processing, Enrichment, Fuel production and being passed through the reactor core the last remaining step is spent fuel disposal.
Answer:
The answer of this question is molecule
Answer ; The question is missing in some details, but here are he details ;
The two naturally occurring isotopes of bromine are
81Br (80.916 amu, 49.31%) and
79Br (78.918 amu, 50.69%).
The two naturally occurring isotopes of chlorine are
37Cl (36.966 amu, 24.23%) and
35Cl (34.969 amu, 75.77%).
Bromine and chlorine combine to form bromine monochloride, BrCl.
Explanation:
The detaile calculation is as shown in the attachment.
Both are oxidation reactions. Burning is just a lot faster than rusting.
