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3 years ago

Which of the following have been determined as the oldest living tree types on Earth? Select all that apply.

Chemistry

1 answer:

fiasKO [112]3 years ago

6 0

Sequoia and Bristle cone pine

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What does ozone in the stratosphere above the earth consist of?

tino4ka555 [31]

Answer:

Ozone is a gas made up of three oxygen atoms (O3). It occurs naturally in small (trace) amounts in the upper atmosphere (the stratosphere). Ozone protects life on Earth from the Sun's ultraviolet (UV) radiation.

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3 years ago

What are the products obtained in the electrolysis of molten nai?

yanalaym [24]

Answer is: sodium (Na) and iodine (I₂).

<span> First ionic bonds in this salt are separeted because of heat:
</span>NaI(l) → Na⁺(l) + I⁻(l).

Reaction of reduction at cathode(-): Na⁺(l) + e⁻ → Na(l) /×2.

2Na⁺(l) + 2e⁻ → 2Na(l).

Reaction of oxidation at anode(+): 2I⁻(l) → I₂(l) + 2e⁻.

The anode is positive and the cathode is negative.

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3 years ago

2. When paleontologists study fossils, which is true of the fossil record that they find?

juin [17]

Answer:

Explanation:

7 0

3 years ago

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Which of the following describes a characteristic of water that makes it cohesive in nature?

kari74 [83]

Answer:

D is answer

Explanation:

8 0

3 years ago

Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is exce

adoni [48]

Answer:

The answer is "10.84 g".

Explanation:

The formula for calculating the number for moles:

$\text{Number of moles }= \frac{\ Mass}{ \ molar \ mass }$

In the given acid nitric:

Owing to the nitric acid mass = $75.9 g$

Nitric acid molar weight $= 63\ \frac{g}{mol}$

If they put values above the formula, they receive:

$\text{moles in nitric acid} = \frac{75.9}{63}$

$=1.204 \ mol$

In the given chemical equation:

$3 NO_2 \ (g) + H_2O \ (l) \longroghtarrow 2 HNO_3 \ (aq) + NO\ (g)$

In this reaction, 2 mols of nitric acid are produced by 1 mole of water.

So, 1.204 moles of nitric acid will be produced:

$= \frac{1}{2} \times 1.204$

$=0.602\ \ \text{mol of water}.$

We are now using Equation 1 in determining the quantity of water:

Water moles $= 0.602\ mol$

Water weight molar $= 18.02 \ \frac{g}{mol}$

$\to 0.602 = \frac{\text{mass of mols}}{ 18.02}\\\\\to \text{mass of mols} = 0.602 \times 18.02\\\\$

$=10.84 \ g$

8 0

3 years ago