Please help me asap !!!!!!!

A car could move at constant speed on an icy curve which is banked for _______________ (all, one, no) speed(s) of the car.

son4ous [18]

All is the answer I believe.

4 0

3 years ago

A 163 ‑turn circular coil of radius 2.65 cm and negligible resistance is immersed in a uniform magnetic field that is perpendicu

stiks02 [169]

Answer:

Explanation:

change in flux = no of turns x area of coil x change in magnetic field

= 163 x π 2.65² x 10⁻⁴ x ( .481 - 0 )

= 1728.84 x10⁻⁴ weber

rate of change of flux = change in flux / time

= 1728.84 x10⁻⁴ / .149

= 11603 x10⁻⁴ V .

volt induced = 1.16 V

current in the circuit

= volt induced / resistance

1.16 / 10.7 = .1084 A

energy dissipated = i²Rt where i is current , R is resistance and t is time.

= .1084² x 10.7 x .149

= .018734 J

= 18.73 mJ .

8 0

3 years ago

When is the kinetic energy of the ball being transformed into gravitational potential energy?

Trava [24]

Answer:

The second option

Explanation:

I am not sure sry

4 0

4 years ago

Read 2 more answers

A 0.110 kg cube of ice (frozen water) is floating in glycerine. The glycerine is in a tall cylinder that has inside radius 3.70

Sonbull [250]

Answer:

the distance by which the height of the liquid in the cylinder change after the ice gets melted = 0.528 cm

Explanation:

The change in volume of glycerin when the ice cube is placed on the surface of the glycerin can be represented as:

$V = \frac{m}{ \rho}$

Given that ;

the mass of the ice cube (m) = 0.11 kg = 0.110 × 10³ g

density of the glycerine ( $\rho$ ) = 1.260 kg/L = 1.260 g/cm³

Then:

V = $\frac{0.110*10^3 \ g}{1.260 \ g/cm^3}$

V = $0.0873*10^3 \ cm^3 (\frac{1L}{10^3 cm^3})$

V = 0.0873 L

Now;Initially the volume of the glycerin before the ice cube starts to melt is:

$V_1 = V_i + V\\\\V_1 = V_i+ 0.0873 \ L$

However; the volume of the water produced by the 0.11 kg ice cube = $0.11*10^3 \ cm^3$

The expression for change in the volume of glycerin after the ice cube starts to melt is as follows:

$V_2 = V_i + V"$

replacing $V"$ with $0.11*10^3 \ cm^3$ ; we have:

$V_2 = V_i (0.11*10^3 \ cm^3 )(\frac{1 \ L }{10^3 \ cm^3})$

$V_2 = V_i + 0.11 \ L$

The overall total change in the volume of the glycerin is illustrated as:

$V_f = V_2 - V_1$

Now; from the foregoing ; lets replace the respective value of $V_2$ and $V_1$ in the above equation ; we have;

$V_f = (V_i + 0.11 \ L) - (V_i + \ 00873 \ L)\\ \\V_f = 0.11 L - 0.0873 \ L\\\\V_f = 0.0227 \ L$

The formula usually known to be the volume of a cylinder is :

$V = \pi r ^2 h$

For the question ; we will have:

$V_f = \pi r ^2 h$

making h the subject of the formula ; we have:

$h = \frac{V_f}{\pi r^2}$

replacing 0.0227 L for $V_f$ and the given value of radius which is = 3.70 cm; we have:

$h = \frac{0.0227 \ L ( \frac{10^3 \ cm^3}{1\ L})}{\pi * (3.70 cm)^2}$

$h = \frac{22.7 \ cm^3}{\pi * (3.70 cm)^2}\\\\h = 0.528 \ \ cm$

Thus ; the distance by which the height of the liquid in the cylinder change after the ice gets melted = 0.528 cm

8 0

4 years ago

The speed of light is 3.0 x 10^8 m/s. If the wavelength of a light wave is 5.8 x 10^-7 m, what is its frequency

ddd [48]

Answer:

The frequency is 517.24 THz

Explanation:

Given:

The speed of light = 3.0 x $10^{8}$ m/s

The wavelength of light wave = 5.8 x $10^{-7}$ m

Frequency = ?

We know that the relation among speed of light, wavelength and frequency is given by

c = νλ , where

c is speed of light

ν is the frequency

λ is the wavelength

To find the frequency(ν):

ν = c / λ

= $\frac{3.0 x 10^{8} ms^{-1} }{5.8 x 10^{-7}m }$

= $\frac{3}{5.8}$ x $10^{15}$

= (3000/5.8) x $10^{12}$

= 517.24 x $10^{12}$ $s^{-1}$

= 517.24 x $10^{12}$ Hz (since 1 $s^{-1}$ = 1 Hz)

= 517.24 THz (Tera Hertz)

Hence the frequency is 517.24 THz.

7 0

3 years ago