(2.00 hours) x (3,600 seconds/hour) = 7,200 seconds

(9.00 minutes) x (60 seconds/minute) = 540 seconds

The record time = (7,200 + 540 + 21) = 7,761 seconds

Distance = (speed) x (time)

= (5.436 m/s) x (7,761 sec) =<span> 42,188.8 meters
________________________________________________
</span>
The official length of the marathon run is 42,195 meters.
If we divide that by the record time in the question, we get

5.4368... m/s .

Rounded to the nearest thousandth, that's 5.437 m/s.

If the question had given the speed as 5.437 instead of 5.436 ,
then we would have calculated the distance to be

(5.437 m/s) x (7,761 sec) =<span> 42,196.6 meters,

4.6 meters closer to the official distance than the answer we did get.
</span>

3 0

3 years ago

Which two charges of a magnet will attract?

ale4655 [162]

Answer:

The other end is called the south pole. When two magnets are brought together, the opposite poles will attract one another, but the like poles will repel one another. This is similar to electric charges.

Explanation:

4 0

3 years ago

Read 2 more answers

Explain how the information from stimuli can become a memory or result in a behavior.

Natali [406]

Answer:

Potentiation, habituation, and sensitization are three ways in which stimuli in the environment produce changes in the nervous system.

5 0

2 years ago

A large asteroid of mass 33900 kg is at rest far away from any planets or stars. A much smaller asteroid, of mass 610 kg, is in

klemol [59]

Answer:

a) 1.2*10^-4 m/s

b) 375 m/s

Explanation:

I assume the large asteroid doesn't move.

The smaller asteroid is affected by an acceleration determined by the universal gravitation law:

a = G * M / d^2

Where

G: universal gravitation constant (6.67*10^-11 m^3/(kg*s^2))

M: mass of the large asteroid (33900 kg)

d: distance between them (146 m)

Then:

a = 6.67*10^-11 * 33900 / 146^2 = 10^-10 m/s^2

I assume the asteroid in a circular orbit, in this case the centripetal acceleration is:

a = v^2/r

Rearranging:

v^2 = a * r

$v = \sqrt{a * r}$

v = \sqrt{10^-10 * 146} = 1.2*10^-4 m/s

If the asteroids have electric charges of 1.18 C and -1.18 C there will be an electric force of:

F = 1/(4π*e0)*(q1*q2)/d^2

Where e0 is the electrical constant (8.85*10^-12 F/m)

F = 1/(4π*8.85*10^-12) (-1.18*1.18)/ 146^2 = -587 kN

On an asteroid witha mass of 610 kg this force causes an acceleration of:

F = m * a

a = F / m

a = 587000 / 610 = 962 m/s^2

With the electric acceleration, the gravitational one is negligible.

The speed is then:

v = \sqrt{962 * 146} = 375 m/s

6 0

3 years ago