Question

The point (- 3, 6) is on a circle with a center at (2, 3) What is the equation of the circle?

Answer 1

Answer:

$(x - 2)^{2} + (y - 3)^{2} = 36$ is the equation of the circle

Step-by-step explanation:

$(x - h)^{2} + (y - k)^{2} = r^{2}$   where (h, k) is the center and r is the radius

In this case h = 2 and k = 3 and r = 6 (see below)

r adius =

$\sqrt{(2 + 3)^{2} + (3 - 6)^{2} } \\= \sqrt{5^{2} + (-3)^{2} } \\= \sqrt{25 + 9\\}\\ = \sqrt{36} = 6$

Therefore,  $(x - 2)^{2} + (y - 3)^{2} = 36$ is the equation of the circle