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Vanyuwa [196]
2 years ago
11

How many hours per year does a high school student spend in school?

Chemistry
2 answers:
krek1111 [17]2 years ago
5 0

Answer:

Around 1260 hours

pishuonlain [190]2 years ago
3 0

Answer:

1260 hours

Explanation:

Depending on your location, different states have different school hours and holidays. However, lets just assume it's the average. The average high school has 180 days of school each year with 7 hour school days.

180(7) = 1260 hours

Of course, this does not account for time spent at home studying, doing homework, tutoring, or other things of the sort.

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What is the oxidation number of sulfur in H2SO3?<br> a. +3<br> b. +1<br> c. +2<br> d. +4
Alla [95]
We need to keep in mind that the compound is neutral.

H2SO3
2(+1)+S+3(-2)=0 (since its neutral)
2+S-6=0
S-4=0
S=4

Therefore the oxidation number for sulfur is +4.
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3 years ago
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What is the volume in liters of 321 g of a liquid with a density of 0.84 g/mL?
garri49 [273]
If we have 321 grams of a liquid, and the density is 0.84 g/mL, then we can easily find the volume of the liquid. We just need to take this 0.84 and multiply that by the number of grams. If we do 321 * 0.84, we get 269.64 mL. This is the volume that this liquid has.Remember this equation for future problems: V = D*M. V meaning volume, D meaning density, and M meaning mass. I hope this helps.
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3 years ago
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An unknown compound with a molar mass of 223.94 g/mol consists of 32.18% c, 4.50% h, and 63.32% cl. find the molecular formula f
Dima020 [189]

The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.

Molar mass of the unknown compound = 223.94 g/mol (given)

Mass of each element present in the unknown compound is determined as:

  • Mass of carbon, C:

\frac{32.18}{100}\times 223.94 = 72.06 g

  • Mass of hydrogen, H:

\frac{4.5}{100}\times 223.94 = 10.08 g

  • Mass of chlorine, Cl:

\frac{63.32}{100}\times 223.94 = 141.79 g

Now, the number of each element in the unknown compound is determined by the formula:

number of moles = \frac{given mass}{molar mass}

  • Number of moles of C:

number of moles = \frac{72.06}{12} = 6.005 mole\simeq 6 mole

  • Number of moles of H:

number of moles = \frac{10.08}{1} = 10.08 mole\simeq 10 mole

  • Number of moles of Cl

number of moles = \frac{141.79}{35.5} = 3.99 mole\simeq 4 mole

Dividing each mole with the smallest number of mole, to determine the empirical formula:

C_{\frac{6}{4}}H_{\frac{10}{4}}Cl_{\frac{10}{4}}

C_{1.5}H_{2.5}Cl_{1}

Multiplying with 2 to convert the numbers in formula into a whole number:

So, the empirical formula is C_{3}H_{5}Cl_{2}.

Empirical mass = 12\times 3+1\times 5+2\times 35.5 = 112 g/mol

In order to determine the molecular formula:

n = \frac{molar mass}{empirical mass}

n = \frac{223.94}{112} = 1.99 \simeq 2

So, the molecular formula is:

2\times C_{3}H_{5}Cl_{2} =  C_{6}H_{10}Cl_{4}

6 0
3 years ago
Nitrogen gas has a density of 4.566 g/L and liquid nitrogen density is 809.0 g/L.
DedPeter [7]

Answer:

OOFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF

Explanation:

IM in 7th dont ask me bro

6 0
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