-4x - 2.4
explanation: 1.3 - 3.7 = -2.4
then you leave the -4x by itself since it’s the only variable
The area of the square pyramid building is the amount of space on it
The maximum base length of the building is 67.42 cm
<h3>How to determine the maximum side length?</h3>
The given parameters are:
Base = b
Slant height (l) = 5b
The lateral surface area is calculated using:
L = 2bl
So, we have:
L = 2 * b * 5b
Evaluate the product
L = 10b^2
The total surface area is calculated using:
T = L + b^2
So, we have:
T = 10b^2 + b^2
Evaluate the sum
T = 11b^2
The maximum surface area is 50,000 square feet
So, we have:
11b^2 = 50000
Divide both sides by 11
b^2 = 50000/11
Take the square root of both sides
b = 67.42
Hence, the maximum base length of the building is 67.42 cm
Read more about square pyramids at:
brainly.com/question/27226486
+60 two negatives equal a positive
Answer:
0
Step-by-step explanation:
6-6 equals 0 and -8 minus 6 equals -14 and 0 divided by equals 0
Solution :
Let
and
represents the proportions of the seeds which germinate among the seeds planted in the soil containing
and
mushroom compost by weight respectively.
To test the null hypothesis
against the alternate hypothesis
.
Let
denotes the respective sample proportions and the
represents the sample size respectively.




The test statistic can be written as :

which under
follows the standard normal distribution.
We reject
at
level of significance, if the P-value
or if 
Now, the value of the test statistics = -1.368928
The critical value = 
P-value = 

= 0.171335
Since the p-value > 0.05 and
, so we fail to reject
at
level of significance.
Hence we conclude that the two population proportion are not significantly different.
Conclusion :
There is not sufficient evidence to conclude that the
of the seeds that
with the percent of the
in the soil.