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rodikova [14]
3 years ago
12

if a scientist is comparing two different earthquake waves and notices that the amplitude is the same for both, but earthquake 1

has a higher frequency than earthquake 2,what conclusion can he make about the overall energy of the earthquake waves ?
Physics
1 answer:
olganol [36]3 years ago
5 0
The one with the higher frequency has more energy than the other.
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Ok, I think this is right but I am not sure:
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3 years ago
Many television sets show 25 images, called 'frames, each second. What is the time interval between one
Firlakuza [10]

Answer:

Given,

Frame rate = 25 frames per second

To find,

Time interval between one frame and the next.

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We can simply solve this numerical problem by using the following process.

Now,

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Total time taken to display the given number of frames (ie. 25 frames) = 1 second

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8 0
2 years ago
A rocket is fired from rest from the ground (y = 0) at time t0 = 0 s. As the rocket is burning its fuel, it moves vertically upw
elixir [45]

Answer:

Explanation:

attached is the solution

6 0
3 years ago
A baton twirler is twirling her aluminum baton in a horizontal circle at a rate of 2.33 revolutions per second. A baton held hor
Nata [24]

Answer:

Explanation:

Given that;

horizontal circle at a rate of 2.33 revolutions per second

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the baton is 60.1 cm in length.

the magnetic field  is oriented at 14.42°

we wil get the area due to rotation of radius of baton is

\Delta A = \frac{1}{2} \Delta \theta R^2

The  formula for the induced emf is

E = \frac{\Delta  \phi}{\Delta  t}

\phi  = \texttt {magnetic flux}

E=\frac{\Delta (BA) }{\Delta  t}

=B\frac{\Delta  A}{\Delta  t}

B is the magnetic field strength

substitute

\texttt {substitute}\  \frac{1}{2} \Delta \theta R^2 \ \ for \Delta  A

E=B\frac{(\Delta  \theta R^3/2)}{\Delta  t} \\\\=\frac{1}{2} BR^2\omega

The magnetic field of the earth is oriented at 14.42

\omega =2.33\\\\L=60.1c,\\\\\theta=14.42\\\\B=0.5

we plug in the values in the equation above

so, the induce EMF will be

E=\frac{1}{2} \times (B\sin \theta)R^2\omega\\\\E=\frac{1}{2} \times (B\sin \theta)(\frac{L}{2} )\omega

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6 0
3 years ago
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