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3 years ago

How man atoms of Mg are in the following equation: (Mg3 N2)4

Chemistry

2 answers:

mariarad [96]3 years ago

3 0

there are 12 atoms of mg in the following equations

sergey [27]3 years ago

3 0

Answer:

$\boxed {\boxed {\sf 12 \ Mg \ atoms }}$

Explanation:

We are given this formula:

$(Mg_3N_2)_4$

We want to find the number of magnesium atoms. We can see that there is a subscript of 3 after the magnesium, so there are 3 magnesium atoms in 1 molecule of the compound.

However, there is a subscript of 4 that comes after the entire compound, so there are actually 4 molecules, with each molecule containing 3 magnesium atoms. Multiply 4 and 3.

3 Mg * 4 = 12 Mg

There are 12 magnesium atoms.

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Consider the reaction Mg₂Si(s) + 4 H₂O(ℓ) → 2 Mg(OH)₂(aq) + SiH₄(g). How many grams of silane gas (SiH₄) are formed if 25.0 g of

Neko [114]

Answer:

10.60 grams of silane gas are formed.

Explanation:

From the reaction:

Mg₂Si(s) + 4H₂O(l) → 2Mg(OH)₂(aq) + SiH₄(g)

We know that the limiting reactant is Mg₂Si, so to find the mass of SiH₄ formed we need to calculate the number of moles of Mg₂Si:

$\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}}$

Where:

m: is the mass of Mg₂Si = 25.0 g

M: is the molar mass of Mg₂Si = 76.69 g/mol

$\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}} = \frac{25.0 g}{76.69 g/mol} = 0.33 moles$

Now, the stoichiometric relation between Mg₂Si and SiH₄ is 1:1 so:

$\eta_{Mg_{2}Si} = \eta_{SiH_{4}} = 0.33 moles$

Finally, the mass of SiH₄ is:

$m_{SiH_{4}} = \eta_{SiH_{4}}*M_{SiH_{4}} = 0.33 moles*32.12 g/mol = 10.60 g$

Therefore, 10.60 grams of silane gas are formed.

I hope it helps you!

3 0

3 years ago

Hydrofluoric acid (HF) can be prepared according to the following equation:

Artemon [7]

Given the balanced equation:

( Reaction type : double replacement)

CaF2 + H2SO4 → CaSO4 + 2HFI

We can determine the number of grams prepared from the quantity of 75.0 H2SO4, and 63.0g of CaF2 by converting these grams to moles per substance.

This can be done by evaluating the atomic mass of each element of the substance, and totaling it to find the molecular mass.

For H2SO4 or hydrogen sulfate it's molecular mass is the sum of the quantity of atomic mass per element. H×2 + S×1 + O×4 = ≈1.01×2 + ≈32.06×1 + ≈16×4 = 2.02 + 32.06 + 64 = 98.08 u (Dalton's or Da) or g / mol.

For CaF2 or calcium fluoride, it's molecular mass adds 1 atomic mass of calcium and 2 atomic masses of fluoride due to the number of atoms.

Ca×1 + F×2 = ≈40.07×1 + ≈19×2 = 40.08 + 38 = 78.07 u (Da or Dalton's) or g / mol.

3 0

3 years ago

Read 2 more answers

If you start with 6 mol of nitrogen gas (N2+) what mass (g) of ammonia (NH4) will be produced?

Yanka [14]

Answer:

204g of NH3

Explanation:

The balanced equation for the reaction is given below:

N2 + 3H2 —> 2NH3

Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.

Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:

Number of mole of NH3 = 12 moles.

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Mass of NH3 =..?

Mass = mole x molar mass

Mass of NH3 = 12 x 17

Mass of NH3 = 204g.

Therefore, 204g of NH3 will be produced from the reaction.

3 0

3 years ago

A sample of sugar (C12H22O11) contains

Lady_Fox [76]

4 moles of sugar.

Explanation:

A mole is defined as the amount of a substance contained in Avogadro's number of particles 6.02 x 10²³.

1 mole of substance = 6.02 x 10²³. molecules

Given that;

the sample of sugar contains 1.505 x 10²³.molecules

The number of moles in this amount of sugar is 4 moles

Learn more:

Number of moles brainly.com/question/13064292

#learnwithBrainly

5 0

3 years ago

GIVING BRAINLY, 5 STARS, FOLLOW AND HEARTS<br>as majority of substances heat up, they:

melamori03 [73]

Answer:

Expand

Explanation:

When you heat up a substance it expands

3 0

3 years ago