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Mrrafil [7]
2 years ago
8

Solve: 5a + 6a = -11 What does A equal? A =

Mathematics
1 answer:
pochemuha2 years ago
8 0

Answer:

a = -1

Step-by-step explanation:

Combine like terms 6a + 5a = 11a

11a = -11

Divide -11 by 11

-11/11 = -1

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15 points to answer this question
Mamont248 [21]

it is none since there is no relation

4 0
3 years ago
Read 2 more answers
Mark ran 875 miles this year in the track club.Mark ran in 52 track meets and ran the same number of miles in each.How many mile
shepuryov [24]

Answer:

The number of miles Mark runs in each track be 16 \frac{43}{52}\ miles

Step-by-step explanation:

Let us assume that the number of miles Mark run in each track meet be x.

As given

Mark ran 875 miles this year in the track club.

Mark ran in 52 track meets and ran the same number of miles in each.

Than the equation becomes

52 × x = 875

x = \frac{875}{52}

x = 16 \frac{43}{52}\ miles

Therefore the number of miles Mark runs in each track be 16 \frac{43}{52}\ miles

7 0
3 years ago
I need to know what x equals
taurus [48]

Answer:

x = 7

Step-by-step explanation:

4 + 5(x + 2) = 7x

4 + 5x + 10 = 7x

5x - 7x = - 4 - 10

- 2x = - 14

- x = - 14/2

- x = - 7

x = 7

8 0
3 years ago
Helppppppppppppppppppppp asap
grandymaker [24]
The answer should be 2x-5
4 0
2 years ago
Read 2 more answers
How to do this question plz answer ​
harina [27]

9514 1404 393

Answer:

  300

Step-by-step explanation:

There are 25 ways to select the first student. After that student is removed from the selection pool for the second student, there are 24 ways to select the second student. This gives 25·24 = 600 ways to select 2 students <em>in a particular order</em>.

Since we don't care about the order, we can divide this number by the number of ways two students can be ordered: AB or BA, 2 ways.

  600/2 = 300

There are 300 ways to pick a combination of two students from 25.

__

<em>Additional comments</em>

This sort of selection (2 out of 25) has a formula for it, and an abbreviation for the formula.

 "n choose k" can be written nCk or C(n, k)

The function is a ratio of factorials:

  nCk = n!/(k!(n-k)!)

If you can typeset this, it is written ...

  \displaystyle\binom{n}{k}=\frac{n!}{k!\cdot(n-k)!}

This is different from the formula for the number of <em>permutations</em> of n things taken k at a time. That would be written nPk or P(n, k) = n!/(n-k)!.

5 0
2 years ago
Read 2 more answers
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