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frosja888 [35]
3 years ago
8

Which of the following molecules has a trigonal planar shape?​

Chemistry
2 answers:
matrenka [14]3 years ago
7 0

Answer:

bf3 is a trigonal shape

Explanation:

no.of pairs = v+m-c+a/2

then it ' ll get 3

so sp2 hybridization

sp2 is a trigonal planar

puteri [66]3 years ago
3 0

Answer:

B

Explanation:

The geometry of the BF3 molecule is called trigonal planar

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Find the mass, in grams, of 3.758 mol CH4. ( show work )
vladimir2022 [97]

Answer:

The mass of CH4 is 60, 29 grams.

Explanation:

We use the weight of the atoms C and H for calculate the molar mass:

Weight of CH4= weight C+ 4 x weight H= 12,01 g/mol +4 x 1,008g/mol=

Weight of CH4 =16, 042 g/mol

1molCH4-----16, 042grams

3,758 mol CH4--X= (3,758 mol CH4 x 16, 042 grams)/1 mol CH4=60,285836 grams

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3 years ago
My heart will go on is from what movie? user: what are chemicals made from oil?
Dima020 [189]
Titanic - it is the theme song by celine dion

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3 years ago
chemist adds of a M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist
Sav [38]

The question is incomplete, here is the complete question:

A chemist adds 370.0 mL of a 2.25 M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist has added to the flask. Round your answer to 3 significant digits

<u>Answer:</u> The mass of iron (III) bromide is 246. grams

<u>Explanation:</u>

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 2.25 M

Molar mass of iron (III) bromide = 295.6 g/mol

Volume of solution = 370.0 mL

Putting values in above equation, we get:

2.25M=\frac{\text{Mass of solute}\times 1000}{295.6\times 370.0}\\\\\text{Mass of solute}=\frac{2.25\times 295.6\times 370.0}{1000}=246.1g

Hence, the mass of iron (III) bromide is 246. grams

4 0
3 years ago
Consider the following elementary steps that make up the mechanism of a certain reaction: 3A→B+C B+2D→C+F Part A What is the ove
saveliy_v [14]

Answer:

A.    3A + 2D → 2C + F

B.    B is an intermediate

C.   rate = k[A]³

 D.  rate = k`[D]²

Explanation:

Part A

The overall reaction is the sum of all the elementary steps:

       3A→B+C

+

       B+2D→C+F

<u>                                         </u>

         3A + 2D → 2C + F

Part B

A reaction intermediate is one that participates in the elementary steps, but it is not a product. Notice B is produced in the first step and consumed in the second, therefore it is an intermediate species.

Part C

The rate law is  the product of the reaction constant, k, times the concentration of the reactants raised to the power of their coefficients in the balanced reaction assuming that it is the slow step in the reaction mechanism.

rate = k[A]³

Part D

Again as in part C:

rate = k [D]²  ( B is not included since as we saw it is an intermediate )

7 0
3 years ago
Assuming steam to be an ideal gas, calculate its specific volume and density at a pressure of 90 lb/in2 and a temperature of 650
Vitek1552 [10]

Answer:

1) Sv = 0.4584 m³/Kg...assuming steam as an ideal gas

% deviation from the values in the steam tables

⇒ % dev = 45 %

2) mass air = 272.617 Kg; assuming air to be an ideal gas

Explanation:

ideal gas:

PV = RTn

molar volume:

⇒ V/n = RT/P

∴ P = 90 psi * ( 0.06895 bar/psi ) = 6.2055 bar

∴ T = 650 F = 343.33 °C = 616.33 K

∴ R = 0.08314 bar.L/mol.K

⇒ V/n = (( 0.08314 )*(616.33 K )) / 6.2055 bar

⇒ V/n = 8.2574 L/mol * ( m³/1000L ) = 8.2574 E-3 m³/mol

specific volume ( Sv ):

∴ Mw = 18.01528 g/mol

⇒ Sv = 8.2574 E-3 m³/mol * ( mol / 18.01528 g ) * ( 1000 g/Kg )

⇒ Sv = 0.4584 m³/Kg

steam table:

∴ P = 6.2055 bar ≅ 6 bar → Sv = 0.3157 m³/Kg

⇒ % deviation = (( 0.4584 - 0.3157 ) / 0.3157) * 100

⇒ % dev = 45.2 %; significant value, assuming  steam to be a ideal gas

2) mass air, assuming ideal gas:

∴ V = 20ft * 35ft * 10ft = 7000ft³ * ( 28.3168 L/ft³ ) = 198217.6 L

∴ P = 17 psi * ( 0.06895 bar/psi ) = 1.172 bar

∴ T = 75 °F = 23.89 °C = 296.89 K

∴ R = 0.08314 bar.L/K.mol

⇒ n air = PV/RT = (( 1.172 )*( 198217.6 )) / (( 0.08314 )*( 296.89 ))

⇒ n air = 9411.616 mol air

∴ Mw air = 28.966 g/mol

⇒ mass air = 9411.616 mol * ( 28.966 g/mol ) = 272616.892 g = 272.617 Kg

7 0
3 years ago
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