The coordinates of the vertices of parallelogram QRST are glven. What would be the coordinates of

I need to fill out the blanks

zzz [600]

Answer:

1. <u>14x</u> and <u>7</u> and <u>9x</u> and <u>3</u>

2. <u>0x</u>

3. <u>4</u>

Step-by-step explanation:

Step 1: Distribute

First, multiply 7 by 2x and 1 to get 14x and 7. Then multiply -3 by 3x and 1 to get -9x and -1

Step 2: Combine like variable terms

Combine 14x, -5x, and -9x, to get 0x.

Step 3: Combine like constant terms

Combine 7 and -3, to get 4.

6 0

3 years ago

Carla packed this box with 1 centimeter cubes what is the volume of the box

shusha [124]

Answer: $60\ cm^3$

Step-by-step explanation:

<h3> The complete exercise is attached.</h3>

You can observe in the picture attached that the box is a rectangular prism.

The volume of a rectangular prism can be found with this formula:

$V=lwh$

Where "l" is the length, "w" is the width and "h" is the height.

You know that the lenght of each side of those cubes is 1 centimeter. Therefore, you can multiply the number of cubes on each side of the box by 1 centimeter in order to find the lenght, the width and the height of the box:

$l=(4)(1\ cm)=4\ cm\\\\w=(3)(1\ cm)=3\ cm\\\\h=(5)(1\ cm)=5\ cm$

Now you can substitute the lenght, the width and the height of the box into the formula shown at the beginning of the explanation:

$V=(4\ cm)(3\ cm)(5\ cm)$

Finally, evaluating, you get that the volume of the box is:

$V=60\ cm^3$

4 0

3 years ago

The variable Z is inversely proportional to X. When X is 6, Z has the value 2. What is the value of z . When x = 13

Simora [160]

Z= k/x

when x is 6, Z= 2

2=k/6

k=2*6

k=12

Z=12/X

when x = 13

Z=12/13

Z=0.923

6 0

3 years ago

A 500-foot cable is attached to the top of a tower and is stretched tight to a point that is 350 feet away from the base of the

Fantom [35]

The angle of depression the cable forms is the arctan of the ratio of the

horizontal distance to the height of the tower which is approximately 35°.

Response:

B. 35°

<h3>Which method can be used to find the angle of depression?</h3>

Given:

Height of the tower = 500-feet

Horizontal distance from the (other) point of attachment of the cable to

the base of the tower = 350-feet.

Required:

The angle of depression formed by the cable.

Solution:

The angle of depression is the angle, θ, the cable forms with the tower

from the top of the tower.

By trigonometric ratios, therefore;

$tan(\theta) = \mathbf{\dfrac{Horizontal \ distance \ of \ cable \ from \ tower}{Height\ of \ tower}}$

Which gives;

$tan(\theta) = \dfrac{350}{500} = \dfrac{7}{10}$

$Angle \ of \ depression, \ \theta = \mathbf{ arctan \left(\dfrac{7}{10} \right) }\approx35^{\circ}$

The best correct option is; <u>B. 35°</u>

Learn more about trigonometric ratios here:

brainly.com/question/13276558

8 0

2 years ago

Find the exact value of sine [2 cosine Superscript negative 1 Baseline (- StartFraction StartRoot 2 EndRoot/2 EndFraction )] = n

Nady [450]

Answer:

$\frac{3\pi}{2}$ .

Step-by-step explanation:

The given expression is

$2\cos^{-1}\left(-\frac{\sqrt{2}}{2}\right)$

It can be rewritten as

$2\cos^{-1}\left(-\frac{1}{\sqrt{2}}\right)$

$2\left [\pi-\cos^{-1}\left(\frac{1}{\sqrt{2}}\right)\right]$ $[\because \cos^{-1}(-x)=\pi-\cos^{-1}(x), x\in [-1,1]]$

$2\left [\pi-\cos^{-1}\left(\cos \frac{\pi}{4}\right)\right]$

$2\left [\pi-\frac{\pi}{4}\right]$

$2\left [\frac{4\pi-\pi}{4}\right]$

$\frac{3\pi}{2}$

Hence, the exact value of given expression is $\frac{3\pi}{2}$ .

3 0

3 years ago