Ask question

Ask question

All categories

2 years ago

11

What’s the empirical formula of a molecule containing 65.5% carbon, 5.5% hydrogen, and 29.0% oxygen?

1 answer:

Yuri [45]2 years ago

5 0

The empirical formula is C₃H₃O.

Moles of C = 65.5/12.01
= 5.45 mol C
Moles of H = 5.5/1
= 5.5 mol H
Moles of O = 29.0/16
= 1.81 mol H
Moles of C: Moles of H: Moles of O =5.45: 5.5: 1.81 =
3.01: 3.0: 1 ≈ 3:3: 1
The empirical formula is C₃H₃O.

You might be interested in

In a 5.609g of H20, how many molecules H20<br> arc<br> present?

nignag [31]

Answer:

1.88 x 10²³molecules of H₂O

Explanation:

Given parameters:

Mass of H₂O = 5.609g

Unknown:

Number of molecules of H₂O = ?

Solution:

To solve this problem, we need to find the number of moles of given compound first.

Number of moles = $\frac{mass}{molar mass}$

Molar mass of H₂O = 2(1) + 16 = 18g/mol

Number of moles = $\frac{5.609}{18}$ = 0.31mole

From mole concept;

1 mole of a substance contains 6.02 x 10²³molecules

0.31 mole of H₂O will therefore contain 0.31 x 6.02 x 10²³molecules

= 1.88 x 10²³molecules of H₂O

8 0

3 years ago

Why does a biker have to peddle harder to travel at a constant speed into the

Anna35 [415]

Answer:

wind has resistance, 10 mph of wind has more than 0 mph

7 0

2 years ago

Someone please help me with this????

tensa zangetsu [6.8K]

Answer:

D po ayan po ang sagot ko salamat po

6 0

3 years ago

Calculate the mass of nitric acid required to make a 250mL solution with 2.40 ph

meriva

The mass of nitric acid required to make the given solution is 0.0627 g.

The given parameters:

<em>Volume of the acid, V = 250 mL</em>
<em>pH of the acid, = 2.4</em>

The hydrogen ion (H⁺) concentration of the nitric acid is calculated as follows;

$H^+ = 10^{-pH}\\\\H^+ = 10^{-2.4}\\\\H^+ = 0.00398$

The molarity of the nitric acid is calculated as follows;

$= 0.00398 \ H^+ \times \frac{1 \ M \ HNO_3}{1 \ H^+} \\\\= 0.00398 \ M$

The number of moles of the nitric acid is calculated as follows;

$moles = M\times L\\\\moles = 0.00398\ M \ \times \ \frac{250 \ mL}{1000} \\\\moles = 9.95 \times 10^{-4} \ mol.$

The molar mass of nitric acid is calculated as;

$HNO_3 = (1) \ + (14) \ + (16 \times 3) = 63 \ g/mol$

The mass of the nitric acid contained in the calculated number of moles is calculated as;

$mass = moles\ \times \ molar \ mass\\\\mass = 9.95\times 10^{-4} \ mol. \ \times \ 63 \ g/mol\\\\mass = 0.0627 \ g$

Thus, the mass of nitric acid required to make the given solution is 0.0627 g.

Learn more about molarity of acids here: brainly.com/question/13864682

3 0

2 years ago

NO LINKS RIGHT ANSWERS ONLY!!!!

Mumz [18]

I think the answer is D

6 0

3 years ago

Read 2 more answers