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Paul [167]
3 years ago
10

Electrons are charged particles. Moving charged particles are a current. There is a current of electrons flowing through a coppe

r wire, as shown below. As the electrons flow through the wire, _______ is generated around the wire.
Chemistry
2 answers:
Naddik [55]3 years ago
6 0

Answer:

As the electrons flow through the wire, <em>electric current </em>is generated around the wire.

Explanation:

The rate of flow of charged particles in a given time is termed as the flow of current. Mostly the charge carriers are termed as electrons in a conductor. So the flow of electrons or movement of charged particles in a given time is the generation of electric current in that current. As the ratio of charge to time at which the charge is moving from one point to another is termed as the current flow in that time.

Current=\frac{Charge}{Time}

Thus, in the present case of electrons flowing in that wire will lead to generating of electric current in the opposite direction around the wire.

bonufazy [111]3 years ago
3 0

Answer:reee

Explanation:

hshgdffdjsnsnxnnxnxnxnxnnxxhhxhxxhxhhxzhzh

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A relatively simple way of estimating profit is to consider the the difference between the cost (the total spent on materials an
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( $ 8,384 )

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-  From given information we know that 1 mol mCPHA provides the oxygens to 1 mol of propene, to make 1 mole of C3H6O so:

               1 mol C3H6      +     1 mol mCPHA      -->    1 mol C3H6O

              ( Mr = 42.08 g)        ( Mr = 172.57 g)          ( Mr = 58.08 g )

- For 1 kg equivalent equation by dividing the whole equation by the highest Molar Mass i.e of C3H6O, the result would be:

              1 mol C3H6      +     1 mol mCPHA      -->    1 mol C3H6O

            ( 42.08 / 58.08 )      ( 172.57 / 58.08 )          ( 1 )

     =     (  0.72452 kg )         ( 2.9712 kg )                  ( 1 kg )    

- However note that the reaction gives only a 96% yield, we scale up the reactants to get that desired 1 kg of C3H6O:

        (0.72452 kg ) (96/100)  + (2.9712 kg) (96/100)  --> 1 kg

     =      ( 0.75471 kg )            + ( 3.095 kg ) ---------------> 1 kg            

- The costs for each component produced:

            (0.75471 kg C3H6) ($10.97 per kg) = $8.279

            (3.095 kg mCPHA) ($5.28 per kg) = $16.342

            (0.75471 kg C3H6) / (0.0210 kg C3H6 / L dichloromethane) = 35.939

            (35.939 Litres dichloromethane) ($2.12 per L) = $ 76.19

- The cost of waste disposal ($5.00 per kilogram of propene oxide)  produced total cost, disregarding labor,energy, & facility costs:

     $8.279 + $16.342 + $ 76.19 + $5.00 = $105.81 per kg C3H6O produced

- Profit: ($258.25 / kg C3H6O) - ($105.81 cost per kg) = $152.44 profit /kg

- Calculate the profit from producing 55.00kg of propene oxide:

             (55.00kg) ($152.44 /kg) = $8,384.2 .. ( $ 8,384 )

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